mc51 Singlechip 8051 c language development and application of control

北京理工大学的鲁棒控制理论讲义,内容很全,很不错-Beijing Polytechnic University robust control theory overhead, as all very, very good

orcad的简明教程，内容详尽，简单易学。-orcad the simple tutorial is very comprehensive and easy.

Cisco E-DI supports perl scripting through the CLI. This feature automates many of the server and network administration tasks. This section explains how to enable and disable the perl scripting service, and how to use Cisco E-DI Perl API for daily tasks. When a perl script is implemented by an administrator or a user, the script automatically inherits the user s security privileges and the user s operational context (either server or network). Each invocation of a

Ti 2407 C用户使用指南-Ti 2407 C users guide

Visual C++NET专业项目实例开发-源代码Project01Chapter08BankOperation-Visual C++ NET development of professional project examples- source code Project01Chapter08BankOperation

VS介绍的第二本书，大家要看看呦，很有用的。我已经看过了。-VS introduction of the second book, we have to look at the Yo, very useful. I have looked at.

传教士与野人问题我们分两种情况考虑。先考虑船在左岸的情况。如果不考虑限制条件，也就是说，船一次可以将三人从左岸运到右岸，然后再有一个人将船送回来。这样，船一个来回可以运过河2人，而船仍然在左岸。而最后剩下的三个人，则可以一次将他们全部从左岸运到右岸。所以，在不考虑限制条件的情况下，也至少需要摆渡[(M+N-3)/2]*2+1次。其中分子上的"－3"表示剩下三个留待最后一次运过去。除以"2"是因为一个来回可以运过去2人，需要[(M+N-3)/2]个来回，而"来回"数不能是小数，需要向上取整，这个用符号[ ]表示。而乘以"2"是因为一个来回相当于两次摆渡，所以要乘以2。而最后的"＋1"，则表示将剩下的3个运过去，需要一次摆渡。-M-C products

java并发编程经典之作，不适合初学者。细细研读受益匪浅-java sweet Junkai之wilt meet the most power-xiang适brazing ， 。细krypton laugh magnetic field Zhan细millet受worship ancestors 浅 Creek

编程珠玑中文版第二版 很经典 值得阅读的一本好书 -good book

网上的电子书《Jbuilder9基础教程》的全部例子源码-online electronic book, "Guide to Jbuilder9 basis," all examples of FOSS