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本程序通过用递归调用的方法实现了汉诺塔问题,这是一个通用的程序,通过输入的层数结果输入到一个out.txt的文件中...
本程序通过用递归调用的方法实现了汉诺塔问题,这是一个通用的程序,通过输入的层数结果输入到一个out.txt的文件中-This procedure by using the method of recursive calls a Tower of Hanoi problem, which is a common procedure, the results by entering into the layers of a document out.txt
- 2022-07-26 21:39:55下载
- 积分:1
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802[1].1d技术规范及说明文档,英文版,但是内容很详尽
802[1].1d技术规范及说明文档,英文版,但是内容很详尽-802 [1] .1 d technical specifications and documentation, in English, but very detailed content
- 2022-05-18 06:07:34下载
- 积分:1
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信息类网站的不错选择,虽然界面比较简单,却具有信息类网站的绝大多数功能,可谓“麻雀虽小,五脏俱全”,很吸引上网用户的眼球。...
信息类网站的不错选择,虽然界面比较简单,却具有信息类网站的绝大多数功能,可谓“麻雀虽小,五脏俱全”,很吸引上网用户的眼球。-Information site good choice, although the interface is relatively simple, but with information of the vast majority of functional categories of sites can be described as
- 2022-02-22 03:59:28下载
- 积分:1
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extaspnet extaspnet extaspnet
ExtAspNet ExtAspNet ExtAspNet- ExtAspNetExtAspNetExtAspNet
- 2022-03-11 05:21:51下载
- 积分:1
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可以使用该工具分析IIS服务器日志,随时了解你的网站的流量及用户所访问页面....
可以使用该工具分析IIS服务器日志,随时了解你的网站的流量及用户所访问页面.-Analysis of the tool can use the IIS server logs, to keep abreast of your site traffic and user visited the page.
- 2022-05-17 05:40:55下载
- 积分:1
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Example 3 project for AVR8515 on C for IAR
Example 3 project for AVR8515 on C for IAR
- 2022-08-19 03:29:54下载
- 积分:1
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as audio and video products, the wide variety and audio data for the lease to se...
由于音像制品的品种繁多,所以音像租赁对于数据的查找,修改,删除和添加等功能的需求量很大,用人工手记的方式显然很烦琐,所以本项目就是为此设计.本项目可以对音像制品进行规范化管理,进而提高经营效率,实现中小音像租赁店日常工作的管理.-as audio and video products, the wide variety and audio data for the lease to search, modify, delete and add features such as the high demand for use of artificial Notes obviously very cumbersome, so this is the project design. This item can be audio-video products for regulation and then mention the high operating efficiency, small and medium-sized audio-video rental shops daily work management.
- 2022-03-09 12:49:40下载
- 积分:1
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一个表,完全用FLASH制作的,效果非常的好,欢迎大家分享
一个表,完全用FLASH制作的,效果非常的好,欢迎大家分享-a table entirely with Flash production, the effect was very good, we are happy to share
- 2022-07-13 08:47:02下载
- 积分:1
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problem with M
排列问题
M个1,N个0的排列(高效率版)
排列数为:c(m+n,n)
对n个0,m个1,我的想法是这样的:
每个排列可以分三段:
全0列,全1列, 子问题列
设各段长:r,s,t .子问题列就是 (n,m) = (n-r,m-s),其中0
- 2022-11-27 09:05:03下载
- 积分:1
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javascriptdiam代码!一个简单的日历控件!
javaScriptdiam 代码!
一个简单的日历控件-javaScriptdiam code! A simple calendar control!
- 2022-03-18 00:17:25下载
- 积分:1