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通过sindrome解码
接下来POW2发现两个大于或等于下一个功率的指数窗口长度(CEIL(LOG2(米))),和POW2计算的功率。使用的两个用于变换长度功率优化FFT算法,虽然在实践通常有使用N = M的执行时间相差不大。为了显现在DFT,情节ofabs(Y),ABS(Y)。^ 2,andlog(ABS(Y))都常见。功率与频率的情节被称为周期图:
- 2023-01-02 04:35:09下载
- 积分:1
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This is an environment in C List prepared by the operation, main set of referenc...
这是一个在C环境下编写的链表操作,主要实现集合的交,并,补操作-This is an environment in C List prepared by the operation, main set of reference and that the fill operation
- 2022-12-24 17:05:04下载
- 积分:1
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bus ticket reservation system
嗨,这个项目基本上是帮你在网上订公共汽车票。它包含javascript和php/mysql函数。小心,这将证明基本上对任何人都有用。尽情享受吧!干杯;
- 2022-08-16 13:20:11下载
- 积分:1
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kruscal的源代码,实现最小生成树的算法,这个是本人自己编的小程序。...
kruscal的源代码,实现最小生成树的算法,这个是本人自己编的小程序。-kruscal the source code to achieve the minimum spanning tree algorithm, this is my own small part of the process.
- 2022-07-05 06:14:17下载
- 积分:1
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校园导游图算法
校园导游图算法--数据结构中有关图的算法 按v求最短路径 按s求信息; 按q退出; 地图在map图像文件里-campus tour map algorithm-- data structure of the plan according to the algorithm for the shortest path v s by seeking information; Q withdrawal by; Maps map image file
- 2022-01-22 07:14:48下载
- 积分:1
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a binary tree using the trigeminal Chain example, the leaves are obtained and th...
一个二叉树的三叉链表运用实例,求出叶子的结点并输出从根结点到该叶子结点的路径!-a binary tree using the trigeminal Chain example, the leaves are obtained and the output node from the Root of leaf nodes in the path!
- 2022-02-21 08:16:56下载
- 积分:1
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“数据结构、算法和程序”这个抽象世界的特殊旅程,以解决现实生活中的许多难题...
“数据结构、算法和程序”这个抽象世界的特殊旅程,以解决现实生活中的许多难题- Data structures, algorithms and procedures of the abstract world of a special journey to solve many real-life problems
- 2023-03-03 18:00:06下载
- 积分:1
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线性非线性 插值程序 用来求出 插值函数的 点具体如内容所属...
线性非线性 插值程序 用来求出 插值函数的 点具体如内容所属-Linear interpolation procedure used to derive non-linear interpolation function, such as the specific content of their
- 2022-02-15 17:12:09下载
- 积分:1
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个人课程设计管理系统,写在一个宿舍的全源码…
个人课程设计写的一个宿舍管理系统的全部源代码-Personal curriculum design management system written in a dormitory full source code
- 2022-01-25 16:20:34下载
- 积分:1
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01 knapsack problem to achieve the most simple, can do more in its expansion, I...
01背包问题最简单实现,可在其上做更多的扩展,不知道可否不用递归用堆栈-01 knapsack problem to achieve the most simple, can do more in its expansion, I do not know can not use recursive stack
- 2022-12-24 12:20:04下载
- 积分:1