Digital Answer eight contests in the case of competition can clearly show that t...

本程序只对一个IP地址进行，如果要对一段IP进行测试，简单修改程序即可。可将发送放在单独的进程 里(使用fork（）），send_icmp里做成循环，每次重新初始化struct sockaddr_in。那么对接收到的数据 进行分析的proc_icmp（）将多一道对IP报头ip->src字段的判断。-this procedure only a pair of IP addresses, IP to a test, a simple change procedures. This can be placed on a separate process (the use of fork ()), causing Lane send_icmp cycle, each re-initialization struct sockaddr_in. Then Butt received the data analysis proc_icmp () will more than one pair of IP header ip-gt; Src field judgment.

-跨平台信息交流，基于 TCP/IP(UDP)，无需服务器，简单易用 可传送文件和文件夹 通讯数据采用 RSA/Blofish 加密-- cross platform information exchange, based on TCP/IP (UDP), does not need the server, simple Yi Yongke transmits the document and the folder communication data uses RSA/Blofish to encrypt

这是一个iSCSI目标器程序,客户端用微软的启动器.-This is an iSCSI target device procedures, the client use Microsoft"s starter.

一个轻量级网络编程框架 前面上传的socketman是跨平台的C++版本，我弄成VC版本了，请站长达人修改一下。-a lightweight framework for network programming uploaded socketman ahead of cross-platform C version, I ended up version of the VC, with many people again.

用vc开发的 FTP 客户端，希望对您的开发有所帮助-Vc developed using FTP client, you would like to help the development of

C++ Socket编程客户端 源码带有debug文件-C++ Socket Programming with a debug client-side source files

C++实现upnp映射!非常好的源代码-C++ to achieve upnp mapping!

可以获取局域网IP、MAC、用户名- May gain local area network IP, MAC, user

列举系统中安装的所有网络协议的程序代码-List of all installed on the system network protocol code

单射函数问题 设函数f将点集S = {0,1, , n -1}映射为f (S) = { f (i) | iÎ S} Í S 。单射函数问题要 从S中选取最大子集X Í S 使f (X )是单射函数。 例如，当n=7， f (S) = {1,0,0,2,2,3,6} Í S 时， X = {0,1,6} Í S 是所求的最大子集。-Injective function, the function f the problem will be the point set based S = (0,1,  , n-1) maps to f (S) = (f (i) | iÎ S) Í S. Injective function of the problem from the largest subset of S, select the X Í S so that f (X) is injective function. For example, when n = 7, f (S) = (1,0,0,2,2,3,6) Í S, when, X = (0,1,6) Í S is a subset of the desired maximum.