ATmega 16演示板的原理图及说明

这是一个老鼠走迷宫的游戏，写的还不错唷！-This is a rat Maze of the game, also wrote a public good!

ntop官方文档及安装配置文件，其中ntop是基于sniffer的一种网络监控工具.-ntop official documentation and installation configuration files, ntop which is based on a network sniffers monitoring tools.

演示了如何生成一个COM组件-demonstration of how to create a COM

主要用于存储和管理以word形式上传的文件后资料-Mainly used for storage and management to word document form to upload data

compiler programming, code something

一个E源码，做学习例子用-An E-source, examples of learning to do with

详细介绍了DNP3通信规约(数据链路层),便于开发相应的软件。-Details of DNP3 communication protocol (data link layer), to facilitate the development of corresponding software.

一:需求分析 1．本程序需掌握树和二叉树的概念及工作原理，运用其原理及概念完成实验.。 2．问题描述： 一个逻辑表达式如果对于其变元的任一种取值都为真，则称为重言式；反之，如果对于其变元的任一种取值都为假，则称为矛盾式；然而，更多的情况下，既非重言式，也非矛盾式。试写一程序，通过真值表判断一个逻辑表达式属于那一类。 3．基本要求： （1）逻辑表达式从终端输入，长度不超过一行。逻辑运算符包括“|”，“&”和“~”, 分别表示或、与和非，运算优先程度递增，但可以有括号改变，即括号内的运算优先。逻辑变元为大写字母。表达式中任何地方都可以含有多个空格符。 （2）若是重言式或矛盾式，可以只“显示True forever”或“False forever”，否则显示“Satisfactible”以及变量名序列，与用户交互。若用户对表达式中变元取一组值，程序就求出并显示逻辑表达式的值。 -1 : a needs analysis. The process required the trees and the binary tree master the concept and principle, to use its principles and the concept of completion of the pilot. . 2. Problem description : If a logical expression for the changes in the yuan"s value for a true, as tautology; Instead, If the changes for the yuan"s value for a fake, then called the contradiction; However, the more the situation, neither tautology. is not a contradiction. Try to write a procedure for the adoption of a truth table judgment logical expression belong into that category. 3. Basic requiremen

很不错的php聊天室源码,提供给大家学习-Very good source php chat room, available to everyone to learn

C臂三维运动仿真C臂在三维移动机器人中的应用