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是一个迷宫程序,程序里用0表示可以走的路,1表示墙,计算机自动寻找出口的程序。...
是一个迷宫程序,程序里用0表示可以走的路,1表示墙,计算机自动寻找出口的程序。-Is a maze procedures, procedures that can be spent 0 path, 1 that the wall, the computer automatically search for the export process.
- 2022-03-03 05:52:01下载
- 积分:1
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Self
自己开发的抓Radius包并保存为文件的代码-Self-developed grasp Radius package and save it as a file code
- 2022-03-01 07:38:42下载
- 积分:1
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This is the classic missionaries and savage the realization of a simple missiona...
这是传教士与野人精典问题的一个简单实现传教士与野人的个数可以输入,船的容量可以输入为交作业写,很马虎,请高手赐教!-This is the classic missionaries and savage the realization of a simple missionary with the Savage Number input, the boat will be able to import perpendicular operation was very sloppy, please enlighten master!
- 2022-03-30 01:44:06下载
- 积分:1
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对通用串行总线#$% 的技术特点和数据传输机制进行了较详细的分析,并讨论了具有#$% 接口
的数字摄像系统的实现。该系统具有一定的实用价值及应用前景。...
对通用串行总线#$% 的技术特点和数据传输机制进行了较详细的分析,并讨论了具有#$% 接口
的数字摄像系统的实现。该系统具有一定的实用价值及应用前景。-23 of the Universal Serial Bus! $ Of the technical features and data transfer mechanism for a more detailed analysis, and discussed with# $ Interface of the digital camera system. The system has a certain practical value and application prospect.
- 2022-01-28 18:32:30下载
- 积分:1
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开发MySql数据库的最新JDBC驱动。
开发MySql数据库的最新JDBC驱动。
- 2022-09-22 06:15:03下载
- 积分:1
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VC6.0写的五子棋游戏,c/c++,益智游戏,源程序。小游戏。
VC6.0写的五子棋游戏,c/c++,益智游戏,源程序。小游戏。-VC6.0 write 331 games, c/c, educational games, and the Source. Small game.
- 2022-05-31 08:38:54下载
- 积分:1
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Windows网络编程(完成端口及网络编程)详细介绍(转载一)
Windows网络编程(完成端口及网络编程)详细介绍(转载一)-Windows network programming (the completion of port and network programming) a detailed introduction (1 reprint)
- 2022-03-07 04:19:10下载
- 积分:1
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ANSYS经典实例汇集.pdf,共收集了72个经典实例,很全,值得一读。...
ANSYS经典实例汇集.pdf,共收集了72个经典实例,很全,值得一读。-ANSYS classic example of pooling. Pdf, collected a total of 72 classic examples, it is the whole, worth reading.
- 2023-05-20 09:10:04下载
- 积分:1
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几何体的体积表面积计算
几何体的体积表面积计算-geometric size of the surface area calculation
- 2022-02-05 19:14:33下载
- 积分:1
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1)设定字节型变量VAR1的内容为35H,编写程序将VAR1的高4位与低4位分离,分别作为低4位保存在RES1和RES2中,这两个变量高4位置0。
2...
1)设定字节型变量VAR1的内容为35H,编写程序将VAR1的高4位与低4位分离,分别作为低4位保存在RES1和RES2中,这两个变量高4位置0。
2)设定32位(二进制)数据0E2597455H(注:最高位为E)保存在变量VAR2中,将该变量中的内容算术左移2位,所得结果仍然保存在VAR2中-1) Set the contents of byte variable VAR1 is 35H, the preparation of the program will VAR1 high 4 and low 4 separation, respectively, as a low 4 bits stored in RES1 and RES2, this high-4 position of the two variables 0.2 ) to set the 32-bit (binary) data 0E2597455H (Note: The highest level of E) stored in the variable VAR2 in the contents of the variable arithmetic left two, the result is still stored in the VAR2 in the
- 2022-09-12 00:15:03下载
- 积分:1