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数值计算的源代码,包括二分法,和弦表,肺伯格算法…
数值计算源代码,包括二分法,弦截法,龙贝格算法,下山法,牛顿迭代法-numerical source code, including the dichotomy, chord sheet, Lung Bergh algorithm, the mountain, the Newton iterative method
- 2022-05-18 20:34:13下载
- 积分:1
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(1)满足均匀分布的[M,N]区间随机数,其中M,N是正整数。
(2) 满足指数分布的[M,N]区间随机数,其中M,N是正整数。...
(1)满足均匀分布的[M,N]区间随机数,其中M,N是正整数。
(2) 满足指数分布的[M,N]区间随机数,其中M,N是正整数。
-(1) satisfy the uniform distribution of [M, N] interval of random numbers, in which M, N be a positive integer. (2) to meet the exponential distribution of [M, N] interval of random numbers, in which M, N be a positive integer.
- 2022-08-16 19:36:01下载
- 积分:1
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Algorithm
算法类,二进制加法的源代码,算法导论上的-Algorithm-type, binary adder
- 2022-03-25 22:19:43下载
- 积分:1
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这个是个简单的关于出票申请的处理,里边还有小型的进销存。...
这个是个简单的关于出票申请的处理,里边还有小型的进销存。-This is a simple application on the handling of the vote, there are small Invoicing inside.
- 2023-07-24 15:10:03下载
- 积分:1
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Given a (undirected) graph G, and G in two points s, t, determined from s to t o...
给定一个(无向)图G,及G中的两点s、t,确定一条从s到t的最短路径。-Given a (undirected) graph G, and G in two points s, t, determined from s to t of a shortest path.
- 2022-01-30 21:36:58下载
- 积分:1
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C#学习基础源码
c#语言快速入门基础代码带注释,主要是针对那些对C#想快速入门的人并且有一定的C++基础的人提供的,快如懂得C#的基本语句和面向对象的基本思想。
- 2022-02-06 09:49:38下载
- 积分:1
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用c实现的判断一个图是否有环,数据结构中的经典算法,输入一个图,然后判断是否有环。...
用c实现的判断一个图是否有环,数据结构中的经典算法,输入一个图,然后判断是否有环。-used to achieve a judgment whether there are plans in Central and data structure of classical algorithm, the importation of a map, and then determine whether there is any ring.
- 2022-08-25 11:34:00下载
- 积分:1
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栈的操作和应用分隔符匹配检验主管…
栈的操作与应用
定界符配对检查
中缀转后缀并求值-stack operation and application delimiter matching inspection superintendent to seek value and Suffix
- 2022-07-06 21:41:57下载
- 积分:1
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求解约瑟夫问题。设有n个人围成一个圆圈坐下,对所有围从的人从某个位置开始编号为1,2,3,……,n,从编号为1的人开始报数1,报数依交进行,报数n的人即出列,下...
求解约瑟夫问题。设有n个人围成一个圆圈坐下,对所有围从的人从某个位置开始编号为1,2,3,……,n,从编号为1的人开始报数1,报数依交进行,报数n的人即出列,下一个人从1开始报数,再报数m的人便是第二个出列的人如此重复下去,直到最后一个人出列为止,于是便得到一个出列的顺序,这称之为约瑟夫(Josephu)问题。-solving problems. N individuals have formed a circle to sit down, all right Wai from the start from a position of No. 1, 2, 3, ..., n, for a number of people reported a few, according to several newspaper pay, the newspaper n ie the out, the next person was from the beginning a few , and reported m is the second out of this series continue to repeat until the final out in a series, then get a series out of order, which called Joseph (Josephu) problem.
- 2022-05-21 23:13:13下载
- 积分:1
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用于WinCE数据库同步与PC机,你可以用问题驱动
wince中用于数据库与PC机的同步,可以实现与pc机数据库的同步更新-used to wince database synchronization with the PC machine, you can drive with pc sync database update
- 2022-10-27 20:05:03下载
- 积分:1