EKFsins

gui设计,在开发各类软件之前可以帮助人们设计软件，并展示设计效果，更好的促进软件研制.(GUI design ，can help you to design GUI,and may help you to show what you will do,so It is more usful to you!)

偏微分方程_编程 Routines in C, C++, Fortran, Java® , Maple® , and MATLAB(Ordinary and Partial Differential Equation Routines in C, C++, Fortran, Java® , Maple® , and MATLAB)

systemvue对通信系统仿真，并进行对数字信号的载波传输仿真实验(systemvue the communications system simulation and digital signal carrier transmission simulation)

matlab hann hamming window FFT DFT DTFT

主要讲述了c的一些应用程序及其在具体地方的应用(C described some of the major applications and applications in specific areas)

说明：  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)

说明：  雷达回波模块当中的干扰噪声以及杂波噪声的仿真程序(Radar module which noise and clutter noise interference emulator)

ActiveMng.cpp MuOnline,DataServer,SourceCode for MuOnline DataServer (zTeam_24.10.13_S6_3)

matlab c++对接matlab c++对接(matlab c++)

VC与MatlabSimulink混合编程的实现与研究(VC and MatlabSimulink HYBRID PROGRAMMING AND RESEARCH)