demonstration algorithm data structure

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一个最短路径算法，具体内容程序开头有介绍-a shortest path algorithm, the specific content of the beginning of a process introduced

是一个ibats和struts的整合的实例，包括多个数据库的代码，（有oracle，MySQL等）-Ibats and struts is a example of the integration, including a number of database code, (with oracle, MySQL, etc.)

我做Excel报表，很老了Rksvr.ini文件文档在以下设置中，您必须更改实际的目录系统[syspath]=D:excelu sample1 temporary=D:excelu sample1与此相关的图片如下：点击查看文档忘记注意这是因为在vfp6下写入，所以选择对vfp8语句稍加改动，请自行修改

SQLite中如何用API操作BLOB类型的字段-how to use SQLite API type BLOB fields

求图的任两结点间的距离，(2) 用二维数组存放C和A ，C是原成本矩阵，A 是求出的距离矩阵 (3) 算法采用三重循环，其中最外层的循环变量必须代表中间结点，中层的循环变量代表头结点而内层循环变量代表尾结点。 (4) 试着把三层循环变量的顺序作些改变，最外层的循环变量仍代表中间结点，而中层循环变量代表尾结点，内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同 (5) 显示结果要清晰易懂 (6) 本题运行结果 -Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q

这是一个用于计算最小生成树的程序。当人们逐个输入每条边的权，再点击生成，便能得到这个图的最小生成树。-This is a used to calculate the minimum spanning tree procedure. When people enter one by one each side of the right, then click generate, will be able to get this graph minimum spanning tree.

我编的学分管理程序,安装包原代码都有!VB入门的好东西-I made the credit management process, the installation package are the original code! VB entry of the good things

Access密码VB源程序!为初学都提供入门之路!-Access VB source code! Beginners to provide entry road!

创建联机调查，并且在真正的时间得到结果。所有结果的计算，而计算到百分比格式。这个项目用于一个组织内，可以从数据库编辑问题。