基于 vb 的图书馆管理

本程序详细 演示了 vc如何连接数据库，对学习mysql与vc++ 有很大帮助-This procedure demonstrated in detail how to connect vc database mysql and studying vc++ has a lot to help

该程序能实现的功能，若活动图有回路则无法计算出关键路径，即解决了判断工程的可行性问题。通过对工程活动的输入，可以建立任意的AOE网进行判断。对于输入的网，可以计算出每个活动的最早开始时间，最迟开始时间和全工程可以完成的最早时间，并找出关键路径和关键活动。-the program can achieve the functional, if a circuit map activities can not be calculated critical path, that is a judgment to resolve the feasibility of the project. Right through the importation of construction activities, we can establish arbitrary judgment AOE network. The network for the importation can be calculated for each of the earliest start time, the latest starting time and the entire project will be completed in the first time, and identify key and critical path activities.

0-1背包问题 可以提供在背包方面遇到问题的学生或者有需要的人.-0-1 knapsack problem can provide a backpack problems encountered students or those who are in need.

用C语言实现数据结构的几种常用结构，还包括关键路径的程序。-C language data structures Several structures, including Critical Path procedures.

我附上我的学校管理程序，你可以检查它的费用，入学，课程内容的目的

*Cube:最大子长方体问题 问题描述: 一个长，宽，高分别为m,n,p的长方体被分割成个m*n*p个小立方体。每个小立方体内有一个整数。 求所给长方体的最大子长方体。子长方体的大小由它所含所有整数之和确定。 */-* Cube : The biggest problem for rectangular Problem description : a long, wide and high respectively m, n, p rectangular cut into the 000 m* n* p small cube. Within each small cube is an integer. Seeking to have the largest rectangular son cuboid. The son of rectangular size it contained all integral and defined.* /

由于时间仓促，所以功能比较简单。有兴趣者可以继续扩展这个系统！-Because time is so short, relatively simple function. Interested persons can continue to expand this system!

数据结构作业题，堆栈和队的使用（大写字母表示魔王语言的词汇；小写字母表示人的词汇语言；魔王语言中包含括号）-Title data structure operations, the stack and force the use of (capital letters that devil language vocabulary lowercase letters that people s vocabulary language devil language contained in brackets)

jobscope jobscope 在线求职人 1） PHP 2） mysql 数据库 3）类

求解约瑟夫问题。设有n个人围成一个圆圈坐下，对所有围从的人从某个位置开始编号为1,2,3，……，n,从编号为1的人开始报数1，报数依交进行，报数n的人即出列，下一个人从1开始报数，再报数m的人便是第二个出列的人如此重复下去，直到最后一个人出列为止，于是便得到一个出列的顺序，这称之为约瑟夫(Josephu)问题。-solving problems. N individuals have formed a circle to sit down, all right Wai from the start from a position of No. 1, 2, 3, ..., n, for a number of people reported a few, according to several newspaper pay, the newspaper n ie the out, the next person was from the beginning a few , and reported m is the second out of this series continue to repeat until the final out in a series, then get a series out of order, which called Joseph (Josephu) problem.