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大数相乘算法,使用C++语言在VC下实现.
大数相乘算法,使用C++语言在VC下实现.-large numbers multiply algorithm, the use of C language in the VC achieve.
- 2022-05-20 23:11:22下载
- 积分:1
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银行家算法!这是一各比较简单的银行家算法,是在c 语言的环境下开发的!...
银行家算法!这是一各比较简单的银行家算法,是在c 语言的环境下开发的!-Banker
- 2022-03-23 20:23:22下载
- 积分:1
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数据结构(C++描述)电子教案,幻灯片
数据结构(C++描述)电子教案,幻灯片-data structure (C) is the electronic lesson plans, slides
- 2022-01-26 07:29:48下载
- 积分:1
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一个Oracle性能监视工具,含几个sql文件
一个Oracle性能监视工具,含几个sql文件- A Oracle performance surveillance tool, contains several sql
document
- 2022-07-01 21:02:31下载
- 积分:1
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is an expression evaluates the algorithm, using the template, can be four operat...
是一个表达式求值的算法,用 模板实现的,可以进行四则运算,支持小数和括号-is an expression evaluates the algorithm, using the template, can be four operators, and parentheses minority support
- 2022-05-15 06:09:19下载
- 积分:1
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这个代码是约瑟夫环链表实现循环的方法,可以帮助理解…
本代码是约瑟夫环的循环链表实现方法,可以帮助理解约瑟夫环的基本原理,及其实现-This code is Joseph Central List realize the cycle method, can help to understand the basic principles of Joseph Ring, and its realization
- 2023-06-02 18:20:03下载
- 积分:1
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多项式与加法和乘法,链表的数据结构是美国的..
用链表实现多项式的加法与乘法,链表是采用数据结构里面的单链表-polynomial with the addition and multiplication, linked list data structure is used inside the single-linked list
- 2022-05-26 16:30:39下载
- 积分:1
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China Mobile calls an inquiry example, help for beginners.
一个中国移动话费查询的例子,对初学者有帮助。-China Mobile calls an inquiry example, help for beginners.
- 2022-04-08 13:19:15下载
- 积分:1
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开发工具 Informix
开发工具 Informix-4gl- Development kit Informix-4gl
- 2022-03-16 21:32:28下载
- 积分:1
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/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means...
迷宫算法(maze)
/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK,
* 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary.
* Each step can be made horizontally or vertically for one more grid (diagonal
* jump is not allowed).
* Your program should print a series of grid coordinates that start from m[0][0]
* and go to m[9][9]
* Hint: No need to find the shortest path, only need to find one path that gets
* you to desitination.
*/
-/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK,
* 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary.
* Each step can be made horizontally or vertically for one more grid (diagonal
* jump is not allowed).
* Your program should print a series of grid coordinates that start from m[0][0]
* and go to m[9][9]
* Hint: No need to find the shortest path, only need to find one path that gets
* you to desitination.
- 2022-08-08 06:28:42下载
- 积分:1