Visual C++ 串口通信技术与工程实践书籍配套（代码）4.3节

一个串口通信的例子，简单的。。可以先学习。-Example of a serial communication, simple. . Can learn.

是关于灵达电源通信规约的串口通信程序，功能是把电源监控器的采集数据上送到规约前置机中。-GOLD comunication rule

实现串口手机短信发送程序很全面的源代码-Serial SMS program is a comprehensive source code

1、本实验箱采用的液晶显示屏内置控制器为SED1520，点阵为122x32，由两片SED1520组成，由E1、E2分别选通，控制显示屏的左右两半屏。-1, the experimental use of the boxes built-in LCD controller for SED1520, to 122x32 dot matrix, composed of two SED1520, E1, E2 respectively strobe control screens around two semi-screen.

这个是8253芯片的两个实例程序，对学习接口的人是有一定帮助的-this is the 8253 case of two procedures, to learn the interface are certainly helpful

vc++编写的adu812下载程序源码，多线程，串口通信-vc prepared adu812 download source, multi-threaded, serial communication

这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x)，绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的书中，都有对表达式运算方法的论述。说实在的，在编译型计算机语言中实现对用户输入表达式的运算是非常困难的。需要对表达式进行扫描，去括号，按照运算符的优先级生成2叉树，然后遍历该树生成逆波兰表达式，再然后通过栈的方法进行运算。如果在表达式中再包含有函数的话......描述起来都麻烦，更不要说用程序实现了:-(-This is a very challenging issue. For user input an arbitrary planar function f (x), mapping out its function curves. Here the most critical technical problems is how to achieve calculated the value of the expression. "Compiling Principle" and "data structure," the book, have right of expression Operational discussed. Indeed, the computer language compiler to achieve expression of the user input operation is very difficult. Need to scan expression to the brackets, in accordance with the priority Operators Generation 2-ary tree, and then traverse the tree generated reverse Polish expression, and then through the stack approach to computing. If the expression again contains the function described ...... these are trouble, not to mention t

VC下读串口的程序，要想进行无线数据传输的话，这是必备的程序-Read serial port under the VC process, in order to carry out wireless data transmission, this is the necessary procedures for

我曾经在工程中使用的部分源代码，有详细的说明-project, I had the use of the source code, a detailed explanation

串口调试测试文件-Serial debug test file