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吐槽网
这个项目主要功能是评论点赞无刷新 还有增删改查
- 2023-02-25 08:20:04下载
- 积分:1
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the simulation windows task management device memory management, interface may b...
本程序模拟windows任务管理器的内存管理,界面可能丑陋点,但是还可以用-the simulation windows task management device memory management, interface may be ugly, but can also use
- 2022-01-28 00:38:58下载
- 积分:1
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国外结构计算程序,FORTRAN高级语言编写,主要用于结构分析。...
国外结构计算程序,FORTRAN高级语言编写,主要用于结构分析。-abroad structure calculation procedures, the High FORTRAN language, mainly for structural analysis.
- 2022-02-05 22:50:48下载
- 积分:1
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DLL under vc++6.0 development technology prototypes, realized the folder travers...
vc++6.0 下的DLL开发技术原型,实现了遍历文件夹下的所有dll文件,并加载,创建自定义菜单,和调用示例。-DLL under vc++6.0 development technology prototypes, realized the folder traversal of all dll files and loaded, create custom menus, and call the sample.
- 2022-02-28 20:44:21下载
- 积分:1
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Frameworks Transactor Client DLL. It converts to API all XML messages required b...
Frameworks Transactor Client DLL. It converts to API all XML messages required by Transactor 2.1
- 2023-02-24 22:45:03下载
- 积分:1
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这是一个关于tree kernel 的文章,很有帮助。比较新的文章
这是一个关于tree kernel 的文章,很有帮助。比较新的文章-This is an article on the tree kernel to deal with it. Relatively new article
- 2022-05-27 09:22:34下载
- 积分:1
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AspcnUP
AspcnUP 上传组件-AspcnUP
- 2022-03-23 00:17:39下载
- 积分:1
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实现定时器算法逻辑,本身不带定时驱动器 TimerLogic实现了一个模拟的时钟,这个时钟的最上一层(类似秒针)是一个256个刻度的盘子,下面四层(类似分钟,时...
实现定时器算法逻辑,本身不带定时驱动器 TimerLogic实现了一个模拟的时钟,这个时钟的最上一层(类似秒针)是一个256个刻度的盘子,下面四层(类似分钟,时针)有刻度是64的小盘子,上层转一圈之后下一层的刻度就走一个刻度。指示当前盘子走到那个刻度是TimerVec(或TimerVecRoot)的index。-achieve timer algorithm logic, it should not take regular drives TimerLogic achieved a simulated clock, the clock on the floor (similar hands of) 256 is a calibration of the dishes, the following four (similar minute hand of a clock) is a scale of 64 small plates, the upper circle turn Zhi after the next level of calibration leave a mark. The current instructions that come calibration plate is TimerVec (or TimerVecRoot) index.
- 2023-03-20 20:00:04下载
- 积分:1
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以深度为k的满二叉树(n=2k
以深度为k的满二叉树(n=2k-1)为例,假设表中每个记录的查找概率相等,即 pi=1/n(1≤i≤n),而树的第i层上有2i-1个结点,因此,折半查找的平均查找长度为:
所以,折半查找的平均时间复杂度为O(log2n)。
-To a depth of k over the binary tree (n = 2k-1) as an example, suppose the table to find the probability of each record the same, that is, pi = 1/n (1 ≤ i ≤ n), and the tree layer of the first i There are 2i-1 nodes, therefore, to find half the average length of search as follows: Therefore, to find half the average time complexity is O (log2n).
- 2023-08-09 03:30:03下载
- 积分:1
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Very good data synchronization software, a small but very powerful features, it...
很不错的数据同步软件,很小但是功能很强大,值得学习-Very good data synchronization software, a small but very powerful features, it is worth learning
- 2022-03-18 13:44:14下载
- 积分:1