扩频通信实用仿真技术PDF

电子书籍 Beginning Ajax，经典-err

ACE的好书vol1,ACE是一个开放源代码框家,为开发高性能,分布式实时和嵌入式系统提供许多组件和模式-books vol1 ACE ACE is an open-source frame, and for the development of high performance, Distributed Real-time and Embedded Systems provides many components and patterns

can 总线的论文，简要介绍了can总线在汽车相关部件的重要应用。较为实用。-can Bus papers, briefed the can bus in the automobile-related components of the important applications. More practical.

HDMI spec 1.3 HDMI接口最新规范-The latest HDMI spec 1.3HDMI interface specification

我下的时候觉得好编程类的-I think under the category of good programming

约瑟夫（Joeph）问题的一种描述是：编号为1,2,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序。-Joseph (Joeph) a description of the problem is: numbered 1,2, ..., n, n individuals sitting clockwise circle, each holding a password (positive integer). An optional start a positive integer as the number of reported upper limit of m, from the first person to embark on the clockwise direction starting from a reported sequence number, to report the number of m stop reported. Those who reported m out of the column, his password as the new m value, from his home in a clockwise direction on the next person started to re-reported from a few, and so on, until all of the column until all the up. Try a program designed to find out the column order.

这是关于matlab的一套资料，十分经典且内容详尽-This is a set of information on matlab, very classic and detailed

swi-205基于JAVA技术的WEB应用开发pdf.rar ibm认证考试的官方辅导材料，很好用，按着考纲写的。-java web development swi-205

可用的C++源代码 想找些电子书籍 N个小时都没有找到 好不容易好象是找到但还坨麻烦-available C source code to find more e-books N hours have not yet been found finally seemed to find trouble but Dazhangtuo

这是一个JAVA入门的小小的学习程序，其主要实现的功能是将输入窗口的信息保存到一个新的文件里-This is a JAVA entry of small learning process, its main function is to input window of preservation to a new document