数字钟设计 数字钟设计 源码

IOout的一段程序 很实用 大家要的自己下载吧-good

字符串字符分类排序-Sort string of characters

请认真书写上传资料的详细功能、包含内容说明(至少要20个字)。尽量不要让站长把-aksdf

将存于DAT1开始的1个8字节BCD相加,结果放在SUM.考虑溢出.-will be stored in the DAT1 began an eight-byte BCD together, the results on SUM. Consider spills.

汇编多媒体教案ppt格式，不错哦！-compilation of multimedia lesson plans ppt format, it is true!

dspic6012A读写24LC02B的例程(用c语言编写)-24LC02B of routines to read and write dspic6012A (using c language)

汇编的时钟驻留程序- Assembly clock resident program

解码程序，用PIC16C57C来解PT2262-Decoding procedure, with PIC16C57C solved PT2262

可驱动8/16位数码管显示或64/128只独立LED的BC8271A芯片中断方式编程代码-can drive 8/16 Digital Display or 64/128 only independent BC8271A LED chip interrupt programming code

学生成绩核算系统的设计与实现（25） 要求：（1）按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 （2）三个成绩对总评成绩的百分比被定义为常数，各占总成绩的30 、30 和40 。 （3）计算每位学生的总评成绩。 （4）计算该班级本课程的总平均成绩。 （5）计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优，89-80为良，79-70为中，69-60为及格，60分以下为不及格。 （6）按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop