超好玩的小游戏.里面有源程序，相关的工发说明

主要介绍USB软件狗的加密算法原理以及ET299软件狗的编程加密-Mainly introduces the USB software dog encryption algorithm principle and the dog" s programming encryption software, ET299

基于vc++的有关摄影测量中近似垂直摄影情况下空中后方交会求解的源代码-based on the photographic measurement of the approximate vertical aerial photography Resection Solving the source code

一个vc++写的推箱子游戏，学2D的朋友可以参考，学3D的也有一定价值-A vc++ Written Sokoban games, school friends can refer to 2D, 3D study also has some value

感谢您使用ASP服务器2.0v。该软件是由中国门户网开发的 一套强大的ASPWEB服务器，使用这个软件的您完全可以抛弃 体积庞大的WINNT，WIN2000服 务器系统及漏洞百出的IIS了。 现在你可以在任何一个系统上调试和发布您的ASP程序了。 目前测试通过的操作系统为：Windows 98；Windows 98 SE；Windows ME；Windows NT+IE4 Windows 2000； Windows XP；Windows .NET Server。现在完全支持ACCESS ，SQL数据库！ 操作说明 1. 安装ASP服务器2.0v。 2. 把您的ASP程序COPY到安装目录中的Web的目录下即可。 -Thank you for using ASP server 2.0v. The software is developed by the Chinese portal ASPWEB a powerful server, using this software, you can discard bulky WINNT, WIN2000 server system and the flaws in IIS has. Now you can debug on any one system and publish your ASP program. The current test of the operating system: Windows 98 Windows 98 SE Windows ME Windows NT+ IE4 Windows 2000 Windows XP Windows. NET Server. Now fully supports ACCESS, SQL database! Instructions 1. Install ASP server 2.0v. 2. Put your ASP program COPY to the installation directory of the Web directory can be.

这是一个简易的扫雷游侠,由于我不会编写界面,所以是一个命令行下的模拟扫雷,:)-This is a summary of mine Paladin, I can not prepare interface there is a command line under the simulated mine, :)

jcl samples

labview的入门教程，可以让你在最短时间内掌握labview的基础知识-LabVIEW introductory tutorial, can let you in the shortest possible time to master the basic knowledge of LabVIEW

一种在很多格子里不断进化的生命进化的小游戏。 它的规则是这样的： 对其中一个网格，如果它的邻居少于两个，则它会死于孤独；如果多于三个，它亦会因拥挤而死。只有当它的邻居数等于二或三时它才会生存到下一代；如果某格原先没有细胞，但它有三个邻居时，会繁衍一个新的细胞。 以上是百度到的介绍。这个程序是我自己写的，只用到了，用的是二维数组，在控制台显示，所以范围比较有限。

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

某公司OA系统源码： 功能较为强大的一套办公系统，可在线角色管理，用户管理，目录管理，模板管理等。 适合用于企业办公。 使用前先打开企业管理器把DB下的数据库附加好 再配置一下web.config中的链接字符串。 还要把WEB目录设置成为虚拟目录。 默认的管理用户及密码都为：51aspx -OA system, a company source: a more powerful set of features of office systems, online role management, user management, directory management, template management. Suitable for business office. Before use Enterprise Manager to open the attached database DB under some good re-configure the link in the web.config string. WEB directory would also like to become a virtual directory settings. The management of the default user and password are: 51aspx