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Firmware: U600XEHI2 The patch allows you to use a camera, MP3-player, video player, voice recorder, JAVA and other features previously unavailable in a discharged battery. And as you will no longer get the message, sound and vibration! Authors - Lindien, das Ported - Valerik0887- Firmware: U600XEHI2 The patch allows you to use a camera, MP3-player, video player, voice recorder, JAVA and other features previously unavailable in a discharged battery. And as you will no longer get the message, sound and vibration! Authors- Lindien, das Ported- Valerik0887

该文件夹给出了卷积编码、交织及维特比软译码仿真程序-The folder is a convolutional coding, weaving and Viterbi decoding software simulation program

c语言写的FFT变换源码,有多个版本,经测试,还比较好用-c language source code of the FFT transform, has multiple versions, tested, is still relatively easy to use

一个简单的猜数字游戏-a simple game viewing

FX2Pipe is a small high speed USB transfer program which can pipe stdin into the FX2 FIFO or back from the FIFO to stdout.

闻亭F28x Flash烧写程序,希望有用-Wintech F28x Flash programmer procedures useful

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

我们将用程序来模拟传统的龟兔赛跑问题。我们将采用随机数生成的方法开发这一问题的仿真程序。 再比赛中共设了70个点，每个点代表比赛跑道可能的一个位置。乌龟和兔从第一个点出发，终点是在第70个点上。 时钟按秒来数计。随着时钟的转动，程序能够根据下述规则来调节乌龟和兔子的位置。动物 跑动类型 占用时间 跑动量乌龟 快走 50% 向右3个点 后滑 20% 向左6个点 慢走 30% 向右1个点兔子 睡觉 20% 不动 大后滑 20% 向右9 个点 快走 10% 向左12个点 小步跳 30% 向右1个点 慢后滑 20% 向左两个点 -procedures we will use to simulate the traditional hand problems. We will adopt the random number generator of the development of the simulation program. Another winner set up 70 points, each point represents the runway competition of a possible location. The turtle and a rabbit from the starting point and finish in the first 70 points. According to the clock to a few seconds of dollars. As the clock turned to procedures under the following rules to regulate turtle and the rabbit"s location. Running types of animals occupying volume running time 50% of turtles to leave three points right after sliding 20% six points left walking 30% a point right rabbits sleep 20% Fixed After a 20% slide right nine points to leave 10% left

移动通信系统中的通信信号调制的MATLAB仿真，包括BPSKQPSK等调制方法-Mobile communication systems Communications of the MATLAB simulation of signal modulation, including BPSK QPSK modulation method, etc.

旅行商问题，两种方法实现，分别是递归回溯和用栈来代替递归的功能的程序-Traveling salesman problem, two methods to achieve, namely, retrospective and the use of recursive stack instead of recursive function procedures