C++程序设计源代码例-C programming source code cases

Convolution program in C

大数据量本地存储系统设计。可处理大量数据。-Large data volume of local storage system design. Can handle large amounts of data.

一款入门级别的益智类游戏源码。 ＝^_^＝-entry-level educational games source. =^_^=

猜数字游戏 * 游戏规则：系统随机从０-１００中选择一个整数， 要求你输入０-１００的数字来猜测，系统所选定的数字 当猜测的数字太大了，就会有 "大太多了，继续努力！" * "有点太大了．" "有点接近了，不过还是大了点" "好紧张啊,大了一点点，快要中了！" 四个等级的提示．同样如果你猜测的太小了，也会有 * "小太多了，怎么可能就那么小？" "有点太小了." "有点接近了，不过还是小了点" "好紧张啊,小了一点点，快要中了！" 四个等级的提示．-*猜数字game rules of the game: the system randomly select from a whole number 0-100, 0-100 ask you to input the number to guess, the system selected figures when the number of too much speculation, there will be a

RSS的开源项目.很方便的解析和生成标准的RSS的XML文件.-RSS revenue item. Very convenient analytical and generate standard RSS XML file.

编译原理转逆波兰式-compiler theory to reverse Polish

三个野人和三个传教士要过河。 (1). 有三个野人和三个传教士要过河。 (2).只有一条船过河，船上每次只能座最多两个人。 (3).任何时候，野人的数量不能比传教士多。否则野人就要吃了传教士。 (4).最终三个野人和三个传教士都要过到河的对面。 -Three Savage and three missionaries must cross the river. (1). There are three wild man and three missionaries must cross the river. (2). There is only one boat to cross the river, each boat can only seat a maximum of two people. (3). Any time the number of savages should not more than the missionaries. Otherwise, we should eat missionary Savage. (4). The final three Savage and three missionaries must cross the river opposite.

摄影测量过程中,进行相片坐标的内定向程序,由框标坐标系转换为像平面坐标系-photogrammetry and remote sensing ,inverse the coordinate

一个简单的小游戏。模拟操作者和电脑猜石头剪子布。-A simple game. And computer simulation of the operator to guess the stone scissors cloth.