企业进销存管理系统

一种基于二维链表的稀疏矩阵模半板类设计 A template Class of sparse matrix. Key technology: bin,2-m linked matrix. constructors: 1.normal constuctor 2.copy constuctor. 3.assignment constructor. Basic operator: 1. addition(sub) of two matrix 2. inverse of a matrix. 3. multiply of two matrix. etc.-based on two-dimensional chain of sparse matrix model semi-plate design of Class A"s template parse matrix. Key technology : bin. 2-m linked matrix. constructors : 1.normal constuctor 2.copy constuctor. 3.ass ignment constructor. Basic operator : 1. addition (sub) 2 matrix of two. inverse of a ma trix. 3. multiply of two matrix. etc

This a simple database management system. It doesn t use any other code (i.e. ODBC, ADO, etc.) and has it s own database file format. I wrote it because I found the other DBMSs code too bulky and hard to debug. It s designed for small applications and I doubt it could handle anything on a large scale. A sample program included in the .zip shows how everything works. The database project is a library project, so you ll have to compile and link with the .lib file to get everything working. Pros: - You have the source code so you know exactly what it is doing - Database files are very small - Small and fast code Cons: - Can t handle large amounts of records (more than 65000ish) - Doesn t support SQL (you have to search the database by cycling through the records and testing them against your constraints) - Each database file can only have one table. -This a simple database management system. It doesn t use any other code (i.e. ODBC, ADO, etc.) and has it s own database file format. I wr

有各种排序算法，比如直接排序，快速排序，希尔排序和选择排序，二叉树排序，链表排序-There are various sorting algorithms, such as direct sequencing, Quick Sort, Hill sort and select sort, tree sort, sort list

8皇后问题的递归求解，c语言实现-8 Queen of recursive solution, c Language

对ACCESS数据库进行读写操作的VC代码-right ACCESS database and write the code VC

论坛中有许多操作Access数据库的介绍、说明，示例代码等资源，但感觉总是不太连贯和全面，给急需想要使用Access数据库做开发的朋友不少遗憾。本代码是一个封装完整的Access数据库类，包括Ole版本协商、数据库优化、数据库连接等等。由于接口非常简单易懂，读者下载后即可直接投入使用，非常方便。不过，由于Access DAO不支持多线程，所以在本代码中没有实现更好的替代方案，这也是读者在使用本代码的过程中需要注意的一个地方。由于本人水平有限，程序中难免会有很多缺陷，还请各位高手指点！

数据结构中的一个试验程序，实现简单的校园导游图功能，提供查找最短路径功能。-data structure of a test procedures, a simple guide campus map function, providing the shortest path search function.

此为编译原理实验报告 学习消除文法左递规算法，了解消除文法左递规在语法分析中的作用 内含 设计算法 目的 源码 等等.... 算法:消除左递归算法为: （1）把文法G的所有非终结符按任一种顺序排列成P1,P2,…Pn 按此顺序执行 （2）FOR i:=1 TO n DO BEGIN FOR j:=1 DO 把形如Pi→Pjγ的规则改写成 Pi→δ1γ δ2γ … δkγ。其中Pj→δ1 δ2 … δk是关于Pj的所有规则； 消除关于Pi规则的直接左递归性 END （3）化简由（2）所得的文法。即去除那些从开始符号出发永远无法到达的非终结符的 产生规则。-to compile this report principle experiment to eliminate learning grammar rules Left delivery algorithm, left the Elimination delivery grammar rules in grammar analysis of the role of the design algorithm containing purpose algorithm source code .... etc. : Elimination left recursive algorithm : (1) grammar, of all non-G website by the end of a paramagnetic Arrange sequence P1, P2, ... Pn implementation of this order (2) FOR i : n = 1 DO TO BEGIN FOR j : = 1 DO put the shape of Pi Gamma approximate rewrite the rules 1 into Pi Gamma Gamma 2 k .... These ions 1 2 ... k ions on all the rules; Pi elimination of the direct rule left recursive END (3) Reduction from (2) from the grammar. Removing that those symbols s

零件切割问题： 给定一块宽度为W的矩形板，矩形板的高度不受限制。现需要从板上分别切割出n个高度为hi，宽度为wi的矩形零件。切割的规则是零件的高度方向与矩形板的高度方向保持一致。问如何切割使得所使用的矩形板的高度h最小？ 任给一个输入实例，能输出切割所需要的实际高度并能用图形演示切割的过程-cutting parts : a given width of the rectangular plate W, the height of rectangular plate unrestricted. Need from the board is cutting out respectively n height of the hi, wi width of the rectangular parts. Cutting parts to the rules of the height of the rectangular plate with a high degree of consistent direction. Asked how cutting makes use of the rectangular plate height h minimum? As an input for example, will cut output by the needs of the high and can be used graphic demonstration of the cutting proce

PB商场零售管理系统源码，无需解压密码，对需要的兄弟有所帮助-PB retail shopping center management system source code, without extracting passwords needed to help brothers