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基于平面波展开 传输矩阵计算2维矩形光子晶体模型 计算可得出相关图谱
handbook中除了参数说明还有参考文献等...
基于平面波展开 传输矩阵计算2维矩形光子晶体模型 计算可得出相关图谱
handbook中除了参数说明还有参考文献等-Plane wave expansion based on the transfer matrix calculation of 2-D model calculation of rectangular photonic crystal patterns can be drawn from the relevant handbook of parameters except that there are references such as
- 2022-02-20 11:11:13下载
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介绍ar,和dtw两种算法,包含一个实际应用的例子
介绍ar,和dtw两种算法,包含一个实际应用的例子-introduced ar, and two algorithms dtw, including a practical application examples
- 2022-05-26 21:12:02下载
- 积分:1
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去除块效应的图像后处理算法文章,用adobe reader打开,详述编码块效应的去除...
去除块效应的图像后处理算法文章,用adobe reader打开,详述编码块效应的去除-Removal of blocking the image post-processing algorithm article, using adobe reader to open, detailed coding block effect removal
- 2022-02-21 10:55:14下载
- 积分:1
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file tokenizar in php simple program for indexing files
file tokenizar in php simple program for indexing files
- 2022-06-15 05:16:31下载
- 积分:1
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protel dxp 实 例 5
protel dxp 实 例 5- protel dxp 实 例 5
- 2022-04-06 21:17:53下载
- 积分:1
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一款经典的小游戏,用C语言编写而成,内容不多,但是包括了全部的功能。...
一款经典的小游戏,用C语言编写而成,内容不多,但是包括了全部的功能。-A classic game, by using C language, which few, but include all the features.
- 2022-01-26 08:05:14下载
- 积分:1
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可以打开图片
可以打开图片-Can open the picture
- 2022-04-21 12:58:41下载
- 积分:1
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大学人事管理系统 大学人事管理系统
大学人事管理系统 大学人事管理系统-University of the University System of Personnel Management Personnel Management System University Personnel Management System
- 2022-08-19 16:01:19下载
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遗传算法求函数最优解
遗传算法求解函数的最大值,且函数只有一个变量。求函数f(x)=x+10*sin(5x)+7*cos(4x),x∈[0,9]。染色体长度为20,交叉概率为0.95,变异概率为0.08,迭代次数为25。 程序修改后可以用于多参数函数的求解。
- 2022-07-16 21:22:56下载
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Find prime numbers prepared by screening the function: void sieve (bool isPrime...
编写筛选查找素数函数:
void sieve(bool isPrime[], int n)
其中isPrime[ ]为一个布尔型数组,n为数组大小。由于2是第一个素数,
所以设置isPrime[0]和isPrime[1]的值为false,并设置其余的元素初值为true。
然后对从4到n-1的每一个i,判断i是否能够被2整除,如果i能够被2整除,则设置isPrime[i]为false。
对从2到n/2的每一个可能的数值重复以上处理,当操作结束时,所有值为true的isPrime[i]所对应的i就是素数,它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
- 2023-03-02 04:45:03下载
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