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利用堆栈进行表达式的计算,表达式可以是加减成除,做的不太复杂,有兴趣的可以进行扩展一下...
利用堆栈进行表达式的计算,表达式可以是加减成除,做的不太复杂,有兴趣的可以进行扩展一下
- 2022-08-09 22:13:07下载
- 积分:1
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GMM检验GMM检验
gmm test gmm test-gmm test gmm test gmm test
- 2022-01-25 15:03:08下载
- 积分:1
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非常之经典的停车场停车问题,解决停车问题的算法
非常之经典的停车场停车问题,解决停车问题的算法-very classic car parks and solving the parking problem Algorithm
- 2023-06-21 01:55:03下载
- 积分:1
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压缩的例子,小脑以PIC 16F877板和之间的通信…
a zipped example of communication between the Cerebellum 16f877 pic board and the CMUcam. There are plenty of comments in the code.
- 2023-07-20 11:40:03下载
- 积分:1
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这是一个猜数字的小游戏,当用户输入一个数字开始猜后,程序会根据用户所猜的数字大小和正确答案来比较,然后提示用户数字是猜大了还是小了,让用户继续猜,直到正确....
这是一个猜数字的小游戏,当用户输入一个数字开始猜后,程序会根据用户所猜的数字大小和正确答案来比较,然后提示用户数字是猜大了还是小了,让用户继续猜,直到正确.-This is a small viewing of the game, when a user input figures began to guess, the procedures under which users guess the number and size compared to the correct answer, and then prompts the user to guess the number is larger or smaller, allows users to guess until right.
- 2023-02-27 20:20:03下载
- 积分:1
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Adventure maze algorithm to achieve a CPP file. TC compiled in the next generati...
迷宫探险算法,一个CPP文件实现。在TC下编译生成。生成的程序是dos exe。LEFT/UP/RIGHT/DOWN 在迷宫中向左、上、右、下走一步。走过的路线显示为黄色,回头路显示为红色。-Adventure maze algorithm to achieve a CPP file. TC compiled in the next generation. Procedure is generated dos exe. LEFT/UP/RIGHT/DOWN in the maze to the left, on right, step down. Through the line shown as yellow, red back.
- 2022-07-18 02:01:47下载
- 积分:1
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这是JAVA的教程,非常详细的讲稿,可以参考
这是JAVA的教程,非常详细的讲稿,可以参考-This is the Java Directory, a very detailed script, they can refer to
- 2022-01-21 19:48:30下载
- 积分:1
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GPS pygarmin
gps pygarmin-0[1].6.tgz
- 2022-03-22 07:00:35下载
- 积分:1
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hdmi agreements detailing the contents of the agreement hdmi, hdmi engaged in th...
详细介绍了hdmi协议的内容,对从事hdmi协议的设计和应用有帮助
- 2023-03-17 15:10:05下载
- 积分:1
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DOS下的秒表程序,是个内存驻留程序
DOS下的秒表程序,是个内存驻留程序-A MTERM program in DOS, simple terminal emulator
- 2022-01-26 05:39:20下载
- 积分:1