如何由单片机升级到DSP中文教程，对需要的同志们很有帮助哦...

多位数除法程序，满足在单片机编程中对除法程序的需要，解决了单片机指令无除法程序的缺点，而且本程序不限制位数。-over the median divider, which meets in MCU Programming division procedures to the needs of SCM solutions division procedures directive without shortcomings, but the procedure does not limit the median.

PHILIPS非接触射频卡RC500的开发技术资料,-PHILIPS non-contact RF Card RC500 development of information technology,

基于AVR单片机的触摸屏控制程序，无需触摸屏驱动芯片也可使用触摸屏。-AVR MCU-based touch-screen control procedures, without a touch screen driver chips can also use the touch screen.

MSP430 149的4×4键盘扫描程序（中断方式），以及JM12864M的液晶驱动程序，谢谢指教-MSP430 149 of 4 × 4 keyboard scan program (interrupt mode), as well as LCD driver JM12864M Thank you advice

单片机的程序 8路输入模拟信号显示电路的设计-Microcomputer Program eight input signals to analog circuit design

功能描述： 利用AT89S51单片机的T0、T1的定时计数器功能，来完成对输入的信号进行 频率计数，计数的频率结果通过8位动态数码管显示出来。要求能够对2－40KHZ 的信号频率进行准确计数，计数误差不超过2/1-Functional Description: Using AT89S51 MCU T0, T1 timing counter function, to complete the input signal frequency counting, counting the frequency of 8 resulted in the adoption of dynamic digital tube display. Request to the 2-40KHZ signal frequency accurately count, counting error of less than 2/1

1.通过键盘、LCD来进行超低功耗实验 2 在一段时间内，如果用户没有进行按键操作，系统将进入“睡眠”－－低功耗状态 3 用户按键后，系统从低功耗状态转到正常的工作状态 4 在非低功耗状态下，程序接收键盘按键执行加法器操作(因为键盘和LCD限制不能实现复杂 5 的功能,如乘法、减法、除法等）.-1. Through the keyboard, LCD for ultra low-power experiment 2 over a period of time, if the user does not have keys to the operation, the system will enter a " sleep" - low-power status 3 users button, the system switch from the low-power state to normal working condition 4 in the non-low-power state, the implementation of procedures to receive the keyboard keys adder operation (because the keyboard and the LCD can not limit the complexity of the functions of 5, such as multiplication, subtraction, division, etc.).

LPC2104 2105 2106 ARM微控制器元件封装库 arm_pcb_sch-LPC2104 2105 2106 ARM microcontroller package components library arm_pcb_sch

三相步进电机的三相六拍工作方式，正转的绕组通电顺序：A、AB、B、BC、C、CA、A，反转的通电顺序：A、AC、C、CB、B、BA、B、A。 由于步进电机转子有一定的惯性以及所带负载的惯性，故步进电机的工作过程中不能及时的启动和停止，在启动时应慢慢的加速到预定速度，在停止前应逐渐减速到停止，否则，将产生失步现象。 步进电机的控制问题可总结为两点： 1、产生工作方式需要的时序脉冲； 2、控制步进电机的速度，使它始终遵循加速、匀速、减速的规律工作。 -Three-phase three-phase stepper motor six shot work, is to order the winding power: A, AB, B, BC, C, CA, A, reverse the order of power: A, AC, C, CB, B, BA, B, A. As the stepper motor rotor has a certain degree of inertia, as well as brought about by the inertia load, the stepper motor during the course of work should not start and stop time, start to be slowly accelerated to a predetermined speed, the stop should be to slow down gradually to the stop, otherwise, will result in out-of-step phenomenon. Stepper motor control problems can be summarized in two points: one, resulting in the need to work the timing pulse 2, control the speed of stepper motor, so that it always followed acceleration, velocity, deceleration of the law of the work.

存储器AT24c02应用源码，avr的mage16单片机控制实例-AT24C02 memory application source code, avr examples of SCM mage16