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* 用拉格朗日插值法依据N个已知数据点即使函数值 * 输入: n--已知数据点的个数N-1 * x--已知数据点第一坐标的N维列向量 * y--已知数据点第二坐标的N维列向量 * xx-插值点第一坐标 * 输出: 函数返回值所求插值点的第二坐标 -* Use Lagrange interpolation method based on N-known data points even function* Input : n-- known data points the number N-1* x-- known data points of the first N-dimensional coordinates listed Vector* y-- Known number stronghold of the second N-dimensional coordinates listed Vector* xx-point first interpolation* Coordinate output : function return values for the second interpolation point coordinates

指纹识别心得，做指纹识别算法的可以参考一下。-Fingerprint identification experience, making fingerprint recognition algorithm that can be reference.

Simple FTP Upload,实现ftp上传功能-Simple FTP Upload, realize ftp upload feature

我总结的泰文的排版规则，对要做泰文排版的，应该很有帮助。-Thai layout rule.

这是一个matlab应用的论文和源代码，拿来和大家共享，希望有用得着的！-This is a Matlab Application papers and source code, and used to share the hope that a worthwhile!

CCTV2008北京奥运会转播表.rar-CCTV2008 Beijing Olympic Games broadcast table. Rar

《数字逻辑》第二版课后题答案，解答超详尽！-" Digital Logic" second edition of the after-school questions answers, answers to super detail!

一个FlexGrid应用的好程序-a good FlexGrid application procedures

编写无错C程序秘诀。使你更快的学习C编程-prepared no mistake C program secret. So the faster you learn C Programming

ali zare zardiny a li zare zardiny -ali zare zardiny ali zare zardiny ali zare zardiny