宾馆管理信息系统

二叉树的先序，中序，后序，按层遍历算法。以中序输入，用‘#’代替叶子节点的子节点输入。-binary tree first sequence, sequence after sequence, layer by traversal algorithm. The order to import, use "#" instead of the leaf nodes for input nodes.

Delphi2005数据库开发教程.rar-Delphi2005shujukukaifa

这是一个魅力 xml c + + 解析器，如果您需要 xpath，请下载我的其他来源 （快速 c + + xpath 语法分析器）.in 代码 xmltest，这测试解析器，向您展示如何使用解析器。

越来越多的书会导致非托管库。这里是一个简单的桌面项目，可以帮助任何研究所管理其图书馆。

一辆汽车加满油后可行驶n公里。旅途中有若干个加油站。设计一个有效算法，指出应在哪些加油站停靠加油，使沿途加油次数最少。对于给定的n和k个加油站位置，编程计算最少加油次数。并证明算法能产生一个最优解-Fill up the car after driving an n km. There are a number of gas stations journey. Design an efficient algorithm that at which stations should stop to refuel along the way so that the least number of refueling. For a given n and k-station location, the calculation program for at least the number of refueling. And to prove that the algorithm can produce an optimal solution

程序存储问题:设有n 个程序{1,2,…, n }要存放在长度为L的磁带上。程序i存放在磁带上的长度是Li ，1≤i≤n 程序存储问题要求确定这n 个程序在磁带上的一个存储方案，使得能够在磁带上存储尽可能多的程序。 编程任务： 对于给定的n个程序存放在磁带上的长度，编程计算磁带上最多可以存储的程序数。 数据输入：由文件input.txt给出输入数据。第一行是正整数n，表示文件个数。接下来的1 行中，有n 个正整数，表示程序存放在磁带上的长度。 结果输出: input.txt output.txt 6 50 5 2 3 13 8 80 20 -program storage problem : There n procedures (1,2, ..., n) to be stored in the length of the L tape. I kept in the proceedings on the tape length is Li, 1 i n storage procedures to seek to establish that n procedures on tape storage of a program that allows the tape to store as much as possible the procedure. Programming tasks : to the n procedures stored in the tape length, calculated programming on tape can store up to the number of procedures. Data input : from the document input.txt given input data. The first line is a positive integer n, said the document number. Following a visit, n is an integer, said procedures stored on tape length. Results output : input.txt output.txt 6 50 5 2 3 13 8 80 20

企业固定资产管理系统-Enterprise Fixed Assets Management System

ORACLE 数据备份,实现oracel数据库的正提，表，记录的分别备份,功能强大，操作方便，可以放心使用，

数据结构大作业：miniStack类的设计-Data structure homework: miniStack Class design

该源代码利用计算机模拟乘法竖式 计算阶乘 将每位数子保存在用new分配的一长字符数组里 在本人的机子上可计算30000!的精确值 用时近60秒-the source code used a computer simulation multiplication calculation factorial shaft will be preserved for each digit used in the distribution of a new long arrays of characters in my machine on computable 30,000! The precise value of time spent nearly 60 seconds