本程序用VHDL语言编程实现FPGA对点阵液晶1602的驱动

opencv motion detection

非常详细的认真的多功能描述和解释了一些道理以及说明-Seriously very detailed description and interpretation of multi-functional logic, as well as some notes

幼儿学习识字和算数的小软件源码,适合3-6岁小孩子用.编的比较简单,如有问题请与我联系.-Children learning to read and write and count small software source code, suitable for 3-6 year-old child with. Made of relatively simple, if there are questions please contact me.

阿苏大嫂风纪扣速度货方思考定界符会三大件开发哈可阿库房萨毒贩-Aso sister-in-law wind speed cargo buckle Ji Thinking delimiter will be the development of Kazakhstan三大件can the Arab-Israeli drug traffickers Treasury Sa

编写筛选查找素数函数： void sieve(bool isPrime[], int n) 其中isPrime[ ]为一个布尔型数组，n为数组大小。由于2是第一个素数， 所以设置isPrime[0]和isPrime[1]的值为false，并设置其余的元素初值为true。 然后对从4到n－1的每一个i，判断i是否能够被2整除，如果i能够被2整除，则设置isPrime[i]为false。 对从2到n/2的每一个可能的数值重复以上处理，当操作结束时，所有值为true的isPrime[i]所对应的i就是素数，它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.

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生成序列的所有组合-generated sequences of all portfolio

一个猜单词游戏，由计算机或一方给出一个单词，另一方根据单词的个数猜出单词。-guess a word game by a computer or one of a word is given, the other party under the words to guess the number of words.

to get GCD(A,B)，and no recursion -to get GCD(A,B),and no recursion

是一本电力系统规划的书，市面上很难买到的。-Is a power system planning books available on the market it is very difficult.