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Windows CE 系统开发 串口通信讲解
Windows CE 系统开发 串口通信讲解-serial communication and Windows CE
- 2022-01-25 16:06:00下载
- 积分:1
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us to do a fixed asset management system, which has some functions for large ref...
我们做的一个固定资产管理系统,该有的功能都有,供大参考-us to do a fixed asset management system, which has some functions for large reference
- 2022-08-05 17:16:50下载
- 积分:1
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WDF解包工具 WDF解包工具 WDF解包工具 WDF解包工具 WDF解包工具
WDF解包工具 WDF解包工具 WDF解包工具 WDF解包工具 WDF解包工具 -wdf Resource Kit readerwdf Resource Kit readerwdf Resource Kit readerwdf Resource Kit readerwdf Resource Kit readerwdf Resource Kit reader
- 2022-01-25 20:12:20下载
- 积分:1
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哈工大 Visual Basic 课程设计
哈工大 Visual Basic 课程设计-HIT Visual Basic Course Design ~ ~
- 2022-04-22 14:51:27下载
- 积分:1
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托盘小程序
此程序为托盘小程序 &nb
- 2022-05-30 20:35:56下载
- 积分:1
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CrossTheMaze
Assume that Edison has found himself in a square-shaped maze of NxN square cells which is surrounded by walls from the outside. In the maze, some of the cells are also walls. Edison can only move between two empty cells in four directions, north, south, west and east. In order to get out of the maze, he drafts a plan. He uses his left hand to lean on the wall and goes by following the wall.
Here is the question, is Edison able to get out of the maze in at most 10,000 steps? If he can make it, output the path. By getting out of the maze, he only needs to be in the exit cell. If the starting cell is the same as the exit, Edison won"t need to move and can directly get out of the maze.
Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case starts with an integer N. N is the size of the maze. Th
- 2022-02-25 06:08:30下载
- 积分:1
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rs232 comm read source program
rs232通信读取源程序
- 2022-02-04 09:15:08下载
- 积分:1
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win2000下的自动关机程序
win2000下的自动关机程序-win2000 automatic pass machine procedure
- 2022-03-14 19:22:37下载
- 积分:1
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锁相环仿真
phase locked loop simulation
- 2022-03-06 10:06:49下载
- 积分:1
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类似中国象棋的小游戏的实现
类似中国象棋的小游戏的实现-similar to a small Chinese chess games to achieve
- 2022-02-05 10:36:28下载
- 积分:1