-
[1]
考勤时间=2005
[1]
考勤时间=2005-10-27
员工编号=1
状态=迟到
上班时间(早)=16:59:40
备注=无
[2]
考勤时间=2005-10-27
员工编号=2
状态=迟到
上班时间(早)=16:59:40
备注=无
[3]
考勤时间=2005-10-27
员工编号=3
状态=迟到
上班时间(早)=16:59:40
备注=无
[6]
考勤时间=2005-10-27
员工编号=6
状态=早退
上班时间(早)=上午 18:52:45
备注=无
下班时间(晚)=上午 18:52:45
[5]
考勤时间=2005-10-27
员工编号=5
状态=早退
上班时间(早)=上午 19:01:40
备注=无
下班时间(晚)=上午 19:01:40
[4]
考勤时间=2005-10-27
员工编号=4
状态=早退
上班时间(早)=上午 19:04:14
备注=无
下班时间(晚)=上午 19:04:14
-[1] time = 2005-10-27 employees attendance number = 1 state = late working hours (early) = 16:59:40 Note = No [2] time = 2005-10-27 employees attendance number = 2 status = late working hours (early) = 16:59:40 Note = No [3] time = 2005-10-27 employees attendance number = 3 state = late working hours (early) = 16:59:40 Note = No [6] Attendance time = 2005-10-27 employee ID = 6 state = leave early to go to work hours (early) = 18:52:45 AM Remarks = no working hours (late) = 18:52:45 AM [5] attendance period = 2005-10-
- 2022-08-15 07:26:19下载
- 积分:1
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Programming of the United States
编程之美--微软技术面试心得:
精确表达浮点数
连连看游戏设计
求二叉树中节点的最大距离
求二进制数中1的个数
寻找发帖“水王”
寻找最大的K个数
饮料供货
中国象棋将帅问题
子数组的最大乘积-Programming of the United States- Microsoft Technical Interview experience: precision floating-point Lianliankan game design to express a binary tree nodes in order to seek the maximum distance in a binary number to find the number of post " Water King" to find the largest number of drinks for the K Cargo Chinese Chess marshals an array of the biggest sub-product of the problem
- 2022-01-25 16:05:51下载
- 积分:1
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DirectDraw扩展的类
DirectDraw扩展类-DirectDraw extension of the class
- 2022-01-28 23:50:21下载
- 积分:1
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rc4算法在wince下的实现。简洁,快速。
rc4算法在wince下的实现。简洁,快速。-rc4 algorithm in wince under implementation. Simple and fast.
- 2022-05-14 03:17:48下载
- 积分:1
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基于boost的asio库的半异步半同步的网络框架可以用来实现Server和Client...
基于boost的asio库的半异步半同步的网络框架可以用来实现Server和Client-Based on boost‘s asio library of semi-asynchronous network of semi-synchronous framework can be used to achieve the Server and Client
- 2023-08-01 08:40:03下载
- 积分:1
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an excellent drive Duikao tool, it can bring a disk copy of all the contents of...
一个出色的硬盘对拷工具,它可以把一个磁盘上的全部内容复制到另外一个磁盘上,也可以把磁盘内容复制为一个磁盘的镜像文件,以后你可以用镜像文件创建一个原始磁盘的拷贝。它可以最大限度地减少你每次安装 Win95 、WinNT 和 OS/2 等操作系统的时间,如果你有好几台配置相似的机器需要安装 Win95 , 你会发现使用 GHOST 使事情变得十分简单。GHOST在 DOS 下运行,并且可以从一张 DOS 引导盘上运行。-an excellent drive Duikao tool, it can bring a disk copy of all the contents of a disk to another, and it can also make disk copy of a disk image file, later you can create an image file copy of the original disk. It can reduce to the maximum every time you install Win95, WinNT and OS/2 operating systems, such as the time, if you have several configuration similar to the need to install Win95 machine, you will find the use of GHOST makes things very simple. GHOST running under DOS, and DOS can be a guide plate operation.
- 2022-02-20 21:01:37下载
- 积分:1
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这是一个显示PNG 格式图片的例子,在Visual C++ 6.0下编译通过!...
这是一个显示PNG 格式图片的例子,在Visual C++ 6.0下编译通过!-This is a display PNG format images example, in Visual C++ 6.0 compiled by!
- 2022-12-21 08:20:03下载
- 积分:1
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机场定退票系统C++builder版本.可以定票退票,选择航线
机场定退票系统C++builder版本.可以定票退票,选择航线-Refund airport system C++ Builder version. Can refund tickets, select the route
- 2022-01-26 02:32:27下载
- 积分:1
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一个通过网路通信的办法实现了对.net C C++程序的万能调试工具...
一个通过网路通信的办法实现了对.net C C++程序的万能调试工具-A network communications through the means of achieving on. Net C C++ programs universal debugging tool
- 2022-06-16 13:38:57下载
- 积分:1
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cplex de jie shao The art and science of road maintenance during adverse winter...
cplex介绍,The art and science of road maintenance during adverse winter conditions has long been hampered by a lack of true integration of weather information into operations. Beginning in 1999,-cplex de jie shao The art and science of road maintenance during adverse winter conditions has long been hampered by a lack of true integration of weather information into operations.
- 2022-05-27 13:18:47下载
- 积分:1