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一:需求分析 1．本程序需掌握树和二叉树的概念及工作原理，运用其原理及概念完成实验.。 2．问题描述： 一个逻辑表达式如果对于其变元的任一种取值都为真，则称为重言式；反之，如果对于其变元的任一种取值都为假，则称为矛盾式；然而，更多的情况下，既非重言式，也非矛盾式。试写一程序，通过真值表判断一个逻辑表达式属于那一类。 3．基本要求： （1）逻辑表达式从终端输入，长度不超过一行。逻辑运算符包括“|”，“&”和“~”, 分别表示或、与和非，运算优先程度递增，但可以有括号改变，即括号内的运算优先。逻辑变元为大写字母。表达式中任何地方都可以含有多个空格符。 （2）若是重言式或矛盾式，可以只“显示True forever”或“False forever”，否则显示“Satisfactible”以及变量名序列，与用户交互。若用户对表达式中变元取一组值，程序就求出并显示逻辑表达式的值。 -1 : a needs analysis. The process required the trees and the binary tree master the concept and principle, to use its principles and the concept of completion of the pilot. . 2. Problem description : If a logical expression for the changes in the yuan"s value for a true, as tautology; Instead, If the changes for the yuan"s value for a fake, then called the contradiction; However, the more the situation, neither tautology. is not a contradiction. Try to write a procedure for the adoption of a truth table judgment logical expression belong into that category. 3. Basic requiremen

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将邮件制作成电子书本-mail produced bookies

用gpl162002的普通io口模拟38kHZ红外发送，接收用串口 -using gpl162002 IO send IRdata

TMS320VC5509A的硬件设计资料，包括两个公司开发板，再加上评估板资料，相信你一定能设计出属于你自己的电路，加油-TMS320VC5509A hardware design information, including development boards of both companies, coupled with the evaluation board information, I believe you will certainly be able to design your own circuits, refueling

this about connectivity of wireless sensors iusing castalia simulator it is nice to s-this is about connectivity of wireless sensors iusing castalia simulator it is nice to see

JAVA编写的游戏 小猫跳 慢慢玩吧-JAVA games prepared kitten jumped slowly玩吧

这是介绍人脸识别的一篇英文综述性的论文，这是上半部分-This is the introduction of a Face Recognition English on the paper, which is a part

酒店管理系统，pb+sql，无密码包括如同堂堂吧 323-hotel management system, pb sql, including passwords without it as a dignified 323

这是一个RPG游戏的源码，希望有兴趣的可以看看，或许有帮助-This is a RPG game source code, I hope interested can look at, perhaps have helped