hard disk read and write simple procedures, able to test disk transfer rate, in...

通过按键控制直流电机的加减速同时通过串口显示当前速度，亦可用串口发送指令来控制电机转速，带有测速显示，使用STM32单片机控制。

面向对象课程作业 使用vc基于模板编写 ――sofabed-object-oriented operations using vc courses based on template preparation-- sofabed

本文档是Arm的整个开发流程，有需要者可以看一下，不错的哦，-This document is Arm of the entire development process, for those who need it can look good Oh,

本来有现成的opencv库来处理项目中要求的获取从摄像头中获取的视频流信息，但是老大考虑到项目中出现的侵权问题，所以让我写一个不涉及第三方库调用window底层视频处理的接口来处理，最后感谢广大的网友力量，我也将自己的成果发不出来供大伙参考。

作者：邵天英 网络流量即时监视。V1.2 本软件运行环境为win2000/NT/XP 无须安装，界面很漂亮。 以线柱的形式即时显示当前的网络流量。 可以查看非常详细的网络配置情况，供您参考。 快捷键为 Ctrl + F12 可以动态显示进，出，总的流量，让你 对当前的网络情况了如直掌。 做为一款系统监视软件，我想他将成为你的好帮手。 可以出售代码。 可以按照你的要求改进功能。 E-Mail: shaotianying0812@sina.com tianying@student.dlut.edu.cn 有任何问题可以与我联系！-Author : Shao-day surveillance network traffic immediately. The V1.2 software operating environment for win2000/NT/XP not required to install, interface and very pretty. Line column to the form shown in the current network traffic. Can View very detailed network configuration, for your reference. Ctrl keys to F12 can be dynamic display of entry, exit, the total flow and let you on the current situation of the network as a direct charge. As a new system monitoring software, I think he will become a good helper you. Code can be sold. According to your request enhancements. E-Mail : shaotianying0812@sina.com tianying@student.dlut.edu.cn have any questions can contact me!

定时关机程序，设定好时间就行-Mytob.BSNotes procedures and set a good time on the line

Exceptional C++: 47 Engineering Puzzles, Programming Problems, and Solutions By Herb Sutter

雪人小程序，用OpenGL vc―++完成-Snowman using OpenGL vc++

Assume that Edison has found himself in a square-shaped maze of NxN square cells which is surrounded by walls from the outside. In the maze, some of the cells are also walls. Edison can only move between two empty cells in four directions, north, south, west and east. In order to get out of the maze, he drafts a plan. He uses his left hand to lean on the wall and goes by following the wall. Here is the question, is Edison able to get out of the maze in at most 10,000 steps? If he can make it, output the path. By getting out of the maze, he only needs to be in the exit cell. If the starting cell is the same as the exit, Edison won"t need to move and can directly get out of the maze. Input The first line of the input gives the number of test cases, T. T test cases follow. Each test case starts with an integer N. N is the size of the maze. Th

自己做的安装程序,看看有没有值得上传源码的价值-own installation procedures, to see what the value of FOSS Upload