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Firmware: U600XEHI2
Disable Card Icon
Removes the icon card.
Auth...
Firmware: U600XEHI2
Disable Card Icon
Removes the icon card.
Author: - ARSik
Ported - Valerik0887- Firmware: U600XEHI2
Disable Card Icon
Removes the icon card.
Author:- ARSik
Ported- Valerik0887
- 2022-03-20 14:54:52下载
- 积分:1
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VC++ Excel操作,介绍了Excel的基本操作
vc++对于excel的操作,介绍了基本的excle的操作-vc++ for excel operation, describes the basic operation of excle
- 2022-06-01 18:04:28下载
- 积分:1
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FM transmitter fault and debugging expert system
调频发射机故障与调试专家系统-FM transmitter fault and debugging expert system
- 2022-08-17 23:43:47下载
- 积分:1
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Collected 9 Particle Swarm Optimization on the paper (in a public journal)
搜集了九篇有关粒子群优化算法的论文(已在公开杂志上发表)-Collected 9 Particle Swarm Optimization on the paper (in a public journal)
- 2023-06-15 00:45:07下载
- 积分:1
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vb方面的编程,条形码编程。希望对大家有用。
vb方面的编程,条形码编程。希望对大家有用。-vb aspects of programming, bar code programming. Want to be useful to everyone.
- 2022-06-21 08:33:40下载
- 积分:1
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宙斯是一个家庭的欧拉(基于网格)的磁
ZEUS is a family of Eulerian (grid based) Magneto-Hydrodynamic codes
(MHD) for use in astrophysics, described in a series of papers by Stone
and Norman (1, 2, 3).
It may be used in Cartesian (XYZ),
cylindrical (ZRP), and spherical (RTP) coordinates.
-ZEUS is a family of Eulerian (grid based) Magneto-Hydrodynamic codes
(MHD) for use in astrophysics, described in a series of papers by Stone
and Norman (1, 2, 3).
It may be used in Cartesian (XYZ),
cylindrical (ZRP), and spherical (RTP) coordinates.
- 2022-02-05 13:26:12下载
- 积分:1
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South Korea 101 007 Bluetooth module describes the features and circuit design,
蓝牙ROK 101 007 介绍了模块的功能和电路设计,-South Korea 101 007 Bluetooth module describes the features and circuit design,
- 2022-01-27 16:22:11下载
- 积分:1
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宝儿
boa-constructor著名的开源开发工具。还要说什么?好像获了好多奖-boa-constructor famous open-source development tools. Still talking about? Like a lot of awards
- 2022-03-24 15:34:31下载
- 积分:1
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CDN网络路由技术、CDN网络路由技术
CDN网络路由技术, CDN网络路由技术-CDN network routing technology, CDN network routing technology
- 2022-04-12 20:18:53下载
- 积分:1
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三个野人和三个传教士要过河。
(1). 有三个野人和三个传教士要过河。
(2).只有一条船过河,船上每次只能座最多两个人。
(3).任何时候,野人的...
三个野人和三个传教士要过河。
(1). 有三个野人和三个传教士要过河。
(2).只有一条船过河,船上每次只能座最多两个人。
(3).任何时候,野人的数量不能比传教士多。否则野人就要吃了传教士。
(4).最终三个野人和三个传教士都要过到河的对面。
-Three Savage and three missionaries must cross the river. (1). There are three wild man and three missionaries must cross the river. (2). There is only one boat to cross the river, each boat can only seat a maximum of two people. (3). Any time the number of savages should not more than the missionaries. Otherwise, we should eat missionary Savage. (4). The final three Savage and three missionaries must cross the river opposite.
- 2022-05-16 02:03:15下载
- 积分:1