VC Rockey2调用函数的源代码

masm file to keep password and name

Complete details of the 5 th unit

软件工程开发文档全套，很全。包含各种文档，想要什么有什么。-Complete set of software engineering development documentation, it is full.

对于商品销售、库存信息，添加、删除、浏览、查询，一个中型的商品信息管理系统。-for merchandise sales, inventory information, add, delete, browse, query, a medium-sized commodity information management system.

ATM银行自动提款机系统，实现业主自动的开户，销户，存钱，提款，查询余额及设置与修改密码服务等事宜的服务系统。-ATM banking ATM system, the account owners, and marketing household, saving money, cash withdrawals, balance inquiries and the provision of services and modify the password of the service system and so on.

用matlab实现障碍期权的复制，并以此给障碍期权定价-Matlab realize with a copy of barrier options and barrier options as to the pricing

用Multi-Agent平台Zeus开发的一个功能完整的开源安全股票交易系统-with Multi-Agent Zeus platform for the development of a functional integrity of the open-source security stock trading system

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected

网上搜的一位牛人的使用linux经验，对初学者很有帮助。-online search of a cow"s use linux experience, useful for beginners.

vb数据库编程练习（1），学习完后可以举一反三。请大家多多指教。-vb database programming practice (1), after learning can draw inferences from. Please exhibitions.