prepared by the steepest decline (equation solution), the attention to the matri...

有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？  程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去掉不满足条件的排列。 

三态树：一个树控件的派生控件，完成item的三种状态-Tri-state tree: A tree control derivative controls, the three states to complete item

ASN.1样例工程代码-ASN.1 type example project code

poj 1451的代码和方法说明,个人原创 -the codes and solution for poj 1451

Modern C++ Design 一书中实现的程序库，全面体现Policy Based Programming 的灵活，提供了诸多设计模式何smart pointer的灵活实现，强烈推荐！--The program library which has been realized in the book >, it embodies the flexibility of Policy Based Programming, and provides the realisation of various design models of the smart pointer, it`s recommended strongly!

计算飞船相对测站的位置矢量单位矢量在赤道坐标系中的三个分量-Calculation of the spacecraft relative position vector of the station unit vector in the equatorial coordinate system of the three subscales

二进制到bcd转换

资源描述 C++编写harris角点检测代码, 一、Harris角点检测基本理论（要讲清楚东西太多，附录提供文档详细说明） 1.1 简略表达： 角点：最直观的印象就是在水平、竖直两个方向上变化均较大的点，即Ix、Iy都较大  边缘：仅在水平、或者仅在竖直方向有较大的变化量，即Ix和Iy只有其一较大  平坦地区：在水平、竖直方向的变化量均较小，即Ix、Iy都较小角点响应 R=det(M)-k*(trace(M)^2) (附录资料给出k=0.04~0.06，opencv指出是0.05-0.5，浮动较大) det(M)=λ1*λ2 trace(M)=λ1+λ2 R取决于M的特征值，对于角点|R|很大，平坦的区域|R|很小，边缘的R为负值。

moment program for electromagnetic computing -moment program for electromagnetic computing

杭州电子科技大学在线系统ACM的1051题，用贪心方法解决-Hangzhou University of Electronic Science and Technology ACM-line system of the 1051 title with a greedy solution