一个由汇编实现的两个数相加，实现简单，比较适合学生

这是我们实习的源代码，是我们老师提供的，希望对大家有所帮助。呵呵，你们认为呢？-This is our attachment to the source code, is provided by the teachers, we hope to help. Oh, do you think?

bios源代码，请对底层的代码有兴趣看下吧-bios source code, the code of the underlying interest Kanxia Bar

4种不同模型的程序 对雷达杂波方针很有用的-is important to radar clutter moleling

一个汇编编译器很好用的-a compilation compiler good use

串口通讯程序,这个程序给出一个参考,并且带645协议部分-Serial communication procedures, which are given a reference, and with part of 645 agreement

epprom yu mcu d yingyong chengxu

注： 电源的 + 12v 是关于 90mA 上升到 110mA 与加载的产出和 20 mhz 频率。 -12V 电源轨是关于 15mA 上升到 23.7mA 11 mhz （峰值负载频率） 与加载与短或电容器 ad811 产品输出。与这种低功耗要求借本身对使用 TPS6735 再加上以下的低功率电感器根据逆变器： C1 44uF，10uF C2，C3 1uF C4 ~ 44uF，C5 22uF D1 1N5817 (肖特基 1A 20V)，10uH L1、 L2 22uH 整个董事会将约 17 毫米 x 43 毫米和电源插头插入 DDS 20 板上的两个 100uF 电容垫，一个电容器转移到

,片选接到p1.5 复位端 p1.4 中断端接到 int0 82c250工作在斜率模式下 ，RS 接51k电阻到地。 2，SJA1000与82C250的接口，逻辑上为SJA1000输出0（显性位），表现为低点平输出给82C250，则82C250输出 差分的低电平。SJA1000输出1（隐性位），表现为高电平或悬空输出给82C250，则82C250输出悬空状态。 3,周立功的中SJA_BCANCONF.ASM中对输出控制寄存器 的TX0的输出 极性的位的定义不对。 还有里面定义有接收错误标志码，不知道何时用。-, The election received a P1.5-chip client p1.4 interrupt reset int0 82c250 client received in the slope mode, RS then 51k resistor to ground. 2, SJA1000 with the 82C250 interface, logic for SJA1000 Output 0 (dominant bit), showing low level output to the 82C250, while the low-level differential output 82C250. SJA1000 Output 1 (recessive), and the performance of the output is high or left vacant to the 82C250, the vacant state 82C250 output. 3, Zhou Ligong in the SJA_BCANCONF.ASM of output control register TX0 output polarity bit the definition of wrong. Inside the definition also has to receive error flag code, I do not know when to use.

C 常用算法程序集 徐士良 编 清华大学出版社 1994.1-C commonly used algorithm for assembly徐士良made Tsinghua University Press 1994.1

在集成电路中，通常采用T型解码网络实现数字量往模拟的转换，再利用运算放大器完成模拟电流变为模拟电压的转换。所以，要把一个数字量变为模拟电压，实际上需要两个环节，先把数字量变为模拟电流，这是由D/A转换器完成的；再将模拟电流变成模拟电压，这是由运算放大器完成的。有时D/A转换器芯片只包含前一个环节，有些D/A转换器则包含两个环节，用前一种芯片时，需要外接运算放大器才能得到模拟电压。-In integrated circuits, the usual T-decode digital networks to analog conversion, and then complete the simulation of the use of op-amp current into the analog voltage conversion. Therefore, it is necessary to become a digital simulation of voltage, in fact, need two links, first into a digital simulation of currents, this is determined by D/A converters completed then simulate current into the analog voltage, this is determined by computing completed amplifier. Sometimes D/A converter chip contains only a part before, some D/A converter includes two aspects, before a chip, the need for external op-amp voltage can be simulated.