华容道源码，游戏爱好者学习编程可以适当参考一下

蓝牙ROK 101 007 介绍了模块的功能和电路设计，-South Korea 101 007 Bluetooth module describes the features and circuit design,

垃圾投递集一款不错的游戏，游戏功能类似，但没有完成，只占很小的比例

算术编码在图象数据压缩标准（如jpeg，jbig）中扮演了重要的角色。在算术编码中，消息用0到1之间的实数进行编码。算术编码用到了两个基本的参数：符号的概率和它的编码间隔。信源符号的概率决定压缩编码的效率，也决定编码过程中信源符号的间隔，而这些间隔包含在0到1之间。编码过程中的间隔决定了符号压缩后的输出。-Arithmetic Coding

这本书主要讲了xna 官方论坛上那个赛车游戏的源码分析和shader编程 c#-This book is mainly about the official forums that xna racing game source code analysis and shader programming

学习java的小程序!很有用的，只要仔细阅读就能学到好多-study java

DOS下的99乘法表输出，供大家学习！ ÿ -Under DOS output 99 multiplication table for everyone to learn!

并行算法，矩阵相乘，MPI。 cannon.c-MPI,MUTPLAY cannon.c

采用vc对pro/engineer 进行二次开发时,vc环境的设置示例.-Using vc on pro/engineer to carry out when the second development, vc sample the environment settings.

很好用，用matlab编的偏最小二乘法，直接在matlab里就可以用。另外带有PLS讲解-Good use, with the partial least squares matlab compiled directly in matlab can be used inside. In addition to explain with PLS

邮票问题:设一国家发行n种不同面值的邮票，并且每封信至多允许贴m张邮票，对于给定的m,n值，写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连续区域以及获得这个区域的各种可能面值的集合。如，当 n=4,m=5,若有面值为（1，4，12，21）的四种邮票，则邮资最大的连续区域为1到71。还有其他面值的四种邮票可组成同样大小的区域吗-stamp issue : Let a national issue n different denominations of the stamps and letters each allow up to m stamp affixed, to the m, n, write an algorithm derived from a postage in an increment of the circumstances, may obtain a postage value of the maximum continuous access to this region and regional various denominations could assemble. For example, when n = 4, m = 5, if the values of (1,4,12,21) of the four stamps, postage largest regional consecutive 1-71. There are four other denominations of the stamps can be the same size as the composition of the region? ?