jathena are the Japanese, open source web server ragnarok. Three are in a writte...

Using GDI and GDI+ mixed drawing rubber band lines_src

VB编程操作Win9X注册表的模块.-VB operation Win9X registry modules.

一个非常简单的printf的源代码-A very simple source code of printf

VC++ 模拟生成彩票号码的简单程序源代码-VC++ simulation generated a simple numbers lottery source code

很好的代码请使用-good use of the codes, please

cocos2dx游戏源码《忍者飞镖打幽灵》 简单的一个小demo，初次接触cocos2dx的一个demo 文档：http://blog.csdn.net/iamlazybone/article/details/16891891 请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报

windows的应用程序界面参考书，其中包含了大部分的函数注释

生命游戏，在一个四周都可以延伸到无限的棋盘上的某个格子中会有一个有机体。每一个有机体在时间t时，会依照环绕着它的8个邻居的特性而决定在时间t+1时是否生存下去-Game of Life, in a four-week can be extended to infinite chessboard a lattice there is a organism. Every organism in terms of time t will be in accordance with its surrounding eight neighbors to determine the characteristics of the time t+ 1 whether to survive

图像处理专业的基础参考程序，能实现由彩色图像读256会读及图像的转换-professional image processing based reference program, able to read by 256 color images will read and image conversion

约瑟夫环（Joseph）问题的一种描述是：编号为1，2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始人选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从它在顺时针方向的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序-Joseph Central (Joseph) a description of the problem is: numbered 1,2, ..., n of n individuals according to a clockwise direction around a circle, each holding a password (positive integer). The beginning of a positive integer as a candidate at a number of upper limit of m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 is reported the number of stops required to report back at a few m. Those who reported m out of his password as the new value of m, in a clockwise direction from the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order