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单片机入门的书,很适合 初学者,U1=89C51
U2=555
U3=MAX232
U4=24C01
U6=X25045看门狗
X1=共阳数...
单片机入门的书,很适合 初学者,U1=89C51
U2=555
U3=MAX232
U4=24C01
U6=X25045看门狗
X1=共阳数码管 -Singlechip book entry, it is suitable for beginners, U1 = 89C51U2 = 555U3 = MAX232U4 = 24C01U6 = X25045 watchdog X1 = total yang digital tube
- 2022-01-28 18:03:24下载
- 积分:1
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视频通用通信控件,免费版本!请注意版权!
视频通用通信控件,免费版本!请注意版权!
- 2023-03-23 19:40:04下载
- 积分:1
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the boat are so strong that it can afford two item
the boat are so strong that it can afford two item
- 2022-02-13 07:50:28下载
- 积分:1
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motor control with pwm
motor control with pwm
- 2023-03-17 02:35:04下载
- 积分:1
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This procedure is to Yuma ephemeris data files into a standard txt convert stand...
本程序是将Yuma的星历数据文件转换成标转换成标准的txt文本格式及第一列位GPS卫星PRN编号,后面为各个卫星的轨道参数-This procedure is to Yuma ephemeris data files into a standard txt convert standard text format and the first GPS satellite PRN numbers faithfully followed for each satellite orbit parameters
- 2022-03-09 13:16:07下载
- 积分:1
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这是一个基本的调查系统,可用于任何网站。
这是一个基本的调查系统,可以在任何网站上使用。-This is a basic survey system which can be used in any website.
- 2022-02-12 12:20:11下载
- 积分:1
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编号为1
编号为1-52张牌,正面向上,从第2张开始,以2为基数,是2的倍数的牌翻一次,直到最后一张牌;然后,从第3张开始,以3为基数,是3的倍数的牌翻一次,直到最后一张牌;然后…从第4张开始,以4为基数,是4的倍数的牌翻一次, 直到最后一张牌;...再依次5的倍数的牌翻一次,6的,7的 直到 以52为基数的 翻过,输出:这时正面向上的牌有哪些?-No. 1-52 card in a positive, progressive, from the first two, with two as the base, 2 is a multiple of the license over time, until finally a license; Then, from the first three starting with three to the base, 3 is a multiple of the license over time, until finally a license; Then ... from the first four starting to four as the base, 4 is a multiple of the license over time, until finally a license; ... followed by the five multiples of the licensing repotted once, 6, 7 to 52 until the base of the turn, the output : At this time positive signs of upward What?
- 2022-01-25 16:12:45下载
- 积分:1
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Empirical mode decomposition process (matlab)
经验模式分解程序(matlab)可以对输入信号进行经验模式分解-Empirical mode decomposition process (matlab)
- 2022-07-16 23:40:09下载
- 积分:1
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该程序用于编写函数:1。的负载和计算…
此程序用fortran编写
功能:
1、是计算在载荷作用下的平面桁架位移以及杆件的轴力。轴力符号规定,受拉为正,受压为负。另外还哼计算支座反力。
2、对桁架的节点编号,采取先编可动节点,接着再编固定节点。
3、计算多工况问题
此程序出自《杆系结构程序设计》,有改动,原程序有错误-the procedure used to prepare fortran functions : 1. calculation of the load under the plane truss rod displacement and the axial force. Symbol axial force, the tension is positive, negative pressure. It also supports anti-hum calculating power. 2, the number of nodes truss, the first series to take movable joints, and then re-allocation fixed nodes. 3, the calculation of multi-state issues this procedure from the "bar structural design process," with changes, the original procedure is wrong
- 2022-02-12 06:40:47下载
- 积分:1
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最优路径 深度优先搜索
最优路径 深度优先搜索-optimal path depth-first search
- 2023-01-04 17:05:03下载
- 积分:1