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motion estimate
运动 估计 快速 算法 之一 :三步搜索-motion estimate
- 2022-01-29 02:31:04下载
- 积分:1
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计算机专业数电答案
计算机专业数电答案-computer professional-- few answers
- 2022-04-01 23:33:51下载
- 积分:1
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龙格库塔法
龙格库塔法-Runge-Kutta method
- 2022-05-13 18:22:46下载
- 积分:1
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该文档为 蓝牙模块DLBM的 使用说明
该文档为 蓝牙模块DLBM的 使用说明-the document to a Bluetooth module for use DLBM
- 2022-07-18 00:20:14下载
- 积分:1
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Detailed introduction AVR
详细介绍AVR-GCC编译器使用说明-Detailed introduction AVR-GCC compiler for use
- 2022-03-02 09:21:39下载
- 积分:1
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joseph环。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始顺...
joseph环。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向的下一个人开始重新从1开始报数,如此下去,直到所有人全部出列为止-joseph ring. Tasks: number is 1,2, ... ..., n of the n individuals in accordance with the clockwise direction around a circle, each person there is only one password (positive integer). One began to choose a positive integer as the number of reported upper limit m, from the first individual to start a clockwise direction since the beginning of the order of one off, back off m stop. Reported m the person out of his password as the new m value, in a clockwise direction from his next re-started from the beginning of one off, it goes on like this until all the column until all
- 2022-05-30 03:56:06下载
- 积分:1
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Zend Framework 入门指南v0.13
Zend Framework 入门指南v0.13-zend framework quickstart
- 2022-03-04 09:22:56下载
- 积分:1
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中断始能应用层协议的开发
中断始能应用层协议的开发-interruption can only application layer protocol development
- 2022-08-25 09:48:28下载
- 积分:1
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用C语言编的两个小小程序,有什么不妥,请给发有EMAIL:zjxpyud2004@126.com
用C语言编的两个小小程序,有什么不妥,请给发有EMAIL:zjxpyud2004@126.com-C language series of the two small procedures, what is wrong with that, we had to EMAIL : zjxpyud2004@126.com
- 2022-03-11 17:29:18下载
- 积分:1
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继承与多态的课程ppt,很实用哦,东南大学虚名教授的课件,值得看,讲的非常详细...
继承与多态的课程ppt,很实用哦,东南大学虚名教授的课件,值得看,讲的非常详细-Inheritance and polymorphism course ppt, very practical oh
- 2022-06-26 18:45:34下载
- 积分:1