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一个带有详细注解的MD5算法source code,便于理解
一个带有详细注解的MD5算法source code,便于理解-with a detailed explanation of the MD5 algorithm source code, easier to understand
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Servlet 视频演示
servlet is a Java 编程语言类用于扩展的功能服务器.虽然 servlet 可以对任何类型的请求作出反应,他们通常用于将承载的应用程序扩展的 web 服务器,因此,他们可以被认为的 Java 小程
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87设计小型微波带通滤波器.pdf
87设计小型微波带通滤波器.pdf-87 design small microwave band-pass filter. Pdf
- 2022-03-02 06:00:44下载
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基于圆检测方法存在的概率图。提出了一个问题。
基于存在概率图的圆检测方法.提出了一种基于存在概率图的圆检测方法, 将图像边缘点共圆结构信息变换为圆存在概率图中的峰, 再通过峰值检测确定圆的参数。该方法能有效地检出边缘不清晰、不完整的圆形轮廓, 具有占用内存少, 阈值物理意义明确的特
点, 较好地解决了标准 HT 圆检测方法中占用内存空间大, 计算效率低的问题。实验结果表明圆存在概率图具有较强的稳定性和分辨能力.-Probability map based on the existence of circle detection method. Presents a probability map based on the existence of circle detection method to image edge points, a total of circular structure of the existence of information is transformed into a round map of the peak probability, and then through the peak detector to determine the parameters of a round. This method is effective in detecting the edge of unclear, incomplete circular profile, with less memory, the physical meaning of the threshold specific characteristics, a better solution to the standard circle detection method HT memory space, the computational efficiency of low- problems. The experimental results show that the existence of the probability circle map has strong stability and resolving power.
- 2022-05-12 18:53:12下载
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将ASCII与Unicode 进行互换的源程序
将ASCII与Unicode 进行互换的源程序 -ASCII and Unicode will be interchangeable source
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operating system materials (2)
操作系统教材(二)-operating system materials (2)
- 2022-12-13 11:00:03下载
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prepare preliminary knowledge of the game, I really can not stand you!
编写游戏的初步知识,我真受不了你!-prepare preliminary knowledge of the game, I really can not stand you!
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小波奇异性检测在负荷数据纠错和平滑处理中的应用.rar
小波奇异性检测在负荷数据纠错和平滑处理中的应用.rar-Singularity Characterization of the load detection and correction of data smoothing processing applications. Rar
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Unix编程常见问题解答
Unix编程常见问题解答-Unix programming FAQ
- 2022-02-22 12:44:58下载
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joseph环。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始顺...
joseph环。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向的下一个人开始重新从1开始报数,如此下去,直到所有人全部出列为止-joseph ring. Tasks: number is 1,2, ... ..., n of the n individuals in accordance with the clockwise direction around a circle, each person there is only one password (positive integer). One began to choose a positive integer as the number of reported upper limit m, from the first individual to start a clockwise direction since the beginning of the order of one off, back off m stop. Reported m the person out of his password as the new m value, in a clockwise direction from his next re-started from the beginning of one off, it goes on like this until all the column until all
- 2022-05-30 03:56:06下载
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