12f629-ir

编译原理大作业。C语言编译器的实现。附大作业的doc文档说明部分。-compiler principles large operations. C language compiler achieved. A large operations doc file narrative.

foxpro-汇编语言命令例解-foxbase建库命令-foxpro实例-(foxpro)

资源描述xilinx ise Verilog语言                                                                                                                                                               &

Matlab通信系统的建模仿真 实验五 直接序列扩频系统的建模与仿真-matlab

汇编语言课程设计《文本阅读器》-Assembly language curriculum design, " text readers"

一个rs-232接口的程序，已经通过调试。收发只用一个定时器。主芯片――8xC751-an rs-232 interface procedures have been adopted debugging. Transceivers only a timer. Main chip-- 8xC751

引导源代码,可以从软盘启动。用汇编软件把代码刷入磁盘第一扇区就可以了(boot code asm)

很详细的汇编小例子程序源代码以及汇编学习课件！忘多多下载(very detailed compilation small example source code and compiled learning courseware! Download forgotten lot)

汇编程序求1个数的四次方，8086测试通过。-compilation procedures for a number of the four sides, the 8086 test.

DEbug 关于制作瑞星杀毒软件密钥盘的源码 MOV BX,200 ;内存基址(0面) MOV DH,00 ;磁头号00 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 3 MOV BX,300 ;内存基址(1面) MOV DH,01 ;磁头号01 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 20 ;返回dos 初学汇编，请各位多多指教！-Debug on the production of Rising antivirus software key source disk MOV BX, 200 memory base address (0 face) MOV DH, 00 head No. 00 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th interruption INT 3 MOV BX, 300 memory base address (1 side) MOV DH, 01 head No. 01 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th