RES_Simulink_Program

说明：  可以得出一个二维数组的所有元素的平均值 适合初学者学习(Averages can draw a two-dimensional array of all the elements For beginners to learn)

time mesure descipation

Chaos synchronization in coupled lasers This is run with Simulink

cs的omp恢复算法,使用恢复矩阵，观测矩阵(The physics of compressive sensing (CS) and the gradient-based recovery algorithms are presented. First, the di® erent forms for CS are summarized. Second, the physical meanings of coherence and measurement are given. Third, the gradient-based recovery algorithms and their geometry explanations are provided. Finally, we conclude the report and give some suggestion for future work.)

matlab demo about reinforcement

modelation of synchronious magnet machine

快速计算菲涅尔衍射光场，将菲涅尔衍射公式转换为快速傅里叶变换FFT，可以直接嵌入程序中使用，对菲涅尔计算全息很有用！(Fast calculation of Fresnel diffraction field, Fresnel diffraction formula will convert the fast Fourier transform FFT, can be directly embedded program using the Fresnel CGH is useful! ! !)

功能：该程序主要用于计算星体运行的部分轨道参数。(Function: The procedure used to calculate the running part of the orbital parameters of stars.)

说明：  一种基于信号二阶统计量的盲源分离方法，SOBI方法，二阶盲辨识方法(SOBI)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)