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说明：  线性预测是语音信号分析中用得比较多的一种方法#&’()算法在线性预测中占有重要地位#格型滤波 器在语音信号分析中起了重要作用$本文采用&’()算法的逆运算对语音信号进行合成#得到了较好的合成效果$ (Linear prediction analysis of speech signal is used more than one way#&amp ' () linear prediction algorithm plays an important role in cell-type filter# signal analysis in speech played an important role in this paper, $ &amp ' () Algorithm of inverse operation of the synthesized speech signal synthesis# get a better result $)

使用matlab设计PID控制器消除系统静态速度误差的方法，主要使用等幅振荡法,并通过WORD给出了传递函数。(PID controller design using matlab static speed error elimination systems approach, the main use of the oscillation amplitude France, and through the WORD gives the transfer function.)

简单的自己写的matlab例程，适合初学者使用下载快速掌握图像处理。(Matlab write their own simple routines for beginners download quickly master image processing.)

hough变换，matlab编程。Hough变换是一种使用表决原理的参数估计技术。其原理是利用图像空间和Hough参数空间的点－线对偶性，把图像空间中的检测问题转换到参数空间。通过在参数空间里进行简单的累加统计，然后在Hough参数空间寻找累加器峰值的方法检测直线。(hough transform, matlab programming. Hough transform is a vote on the principle of using a parameter estimation techniques. The principle is the point of the image space using the Hough parameter space and line- duality converting the detection problem in the image space to the parameter space. By a simple statistical accumulated in the parameter space, and then in the Hough parameter space to find a method of detecting the peak accumulator line.)

Tutorial for cmex in matlab builing c(cmex matlab)

Algoritmo de rls en matlab, archivo .m

提供两个小程序，一个是多重分形谱算法；另一个是盒子维数的计算。(Provide two small programs, one is multifractal spectrum algorithm the other is the calculation of box dimension.)

kalman 滤波的 matlab 程序 (Kalman filtering procedures Matlab)

am modulation and demodulation matlab full code

x0 = ones(2,2) Make a starting guess at the solution options = optimset( Display , off ) Turn off Display [x,Fval,exitflag] = fsolve(@myfun,x0,options) The solution is x = -0.1291 0.8602 1.2903 1.1612 Fval = 1.0e-009 * -0.1619 0.0776 0.1161 -0.0469 exitflag = 1 and the residual is close to zero. sum(sum(Fval.*Fval)) ans = 4.7915e-020