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est_daopu_len
运动模糊图像的复原,采用倒谱法估计模糊尺度,编写代码,适合初学者学习与理解。含图,可运行测试(Restoration of motion blurred images using fuzzy scale cepstrum estimation, writing code, suitable for beginners to learn and understand. Including maps, can run the test)
- 2010-07-02 20:24:12下载
- 积分:1
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Qfilters_point_detector
Quadrature filters point detector in scale-space
- 2010-03-14 21:02:13下载
- 积分:1
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fuzzymlsimu
模糊控制仿真模型,采用MATLAB进行模糊控制系统仿真(FUZZY CONTROL SIMULINK)
- 2013-11-26 13:27:35下载
- 积分:1
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MatlabWork0
说明: vhdl 初学例程,对于初学者有很大的参考价值哦(VHDL beginner routines for beginners have great reference value oh)
- 2006-04-02 01:50:12下载
- 积分:1
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lobe
采用完全离散法绘制切削加工过程中的颤振稳定性叶瓣图(The full discrete method is used to map the stability of the leaf flap)
- 2020-11-16 15:29:40下载
- 积分:1
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jiyuMatlab
基于Matlab的红外图像的轮廓特征提取 基于Matlab的红外图像的轮廓特征提取 (Matlab-based infrared images of the contour feature extraction Matlab-based infrared images of the contour feature extraction)
- 2011-05-09 15:34:35下载
- 积分:1
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PCA-BEL(ToolBox1.0)
又提供一基于生理的情感神经网络,包含杏仁体,丘脑,视觉神经等重要元素,可用于分类与预测,性能优越于SVM,BP(The use of neural network based on emotional physiology, contains important elements of the amygdala, thalamus, optic nerve, etc., can be used for classification and prediction, superior performance to SVM)
- 2015-03-17 18:23:36下载
- 积分:1
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PF
此程序是计算电力系统潮流的通解,通过支路法不断更新参数(This procedure is the general solution of the power flow calculation, continuously updated through the branch method parameters)
- 2013-12-09 15:15:05下载
- 积分:1
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MATlab12
it may be worth to see here is a matlab example code
- 2013-03-25 08:47:42下载
- 积分:1
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szfxsy1
实验一:三次样条插值(P56,例6)
一、实验目的:
1) 掌握三次样条插值的运用
2) 了解拉格朗日插值在高次上的误差
二、实验环境:Matlab6.5
三、实验内容:
1) 给定函数f(x)=1/(1+x2),-5<=x<=5,节点xk=-5+k,(k=0,1,2…10),用三次样条插值求S10(x),S10’(-5)=f’(-5),S10’(5)=f’(5)。
2)作原函数f(x),拉格朗日插值函数Ln(x),三次样条差值函数Sn(x)。画出三个函数的图像,比较它们的区别。
(Experiment I: cubic spline interpolation (P56, cases of 6) First, the experiment was: 1) cubic spline interpolation to master the use of 2) understanding of Lagrange interpolation in high-error second, experimental environment: Matlab6 .5 c, experimental elements: 1) a given function f (x) = 1/(1+ x2),-5 <= x <= 5, node xk =- 5+ k, (k = 0,1,2 ... 10), using cubic spline interpolation for S10 (x), S10 (-5) = f (-5), S10 (5) = f (5). 2) for the original function f (x), the Lagrange interpolation function Ln (x), cubic spline difference function Sn (x). Draw the three functions of images, compare the difference between them.)
- 2009-01-18 23:06:15下载
- 积分:1