登录
首页 » Python » 证书加密解密

证书加密解密

于 2017-12-20 发布
0 263
下载积分: 1 下载次数: 1

代码说明:

说明:  本次实验是基于广泛测试的公开加密库来实现数字签名服务。这里选择了 M2Crypto 加密库来实现,M2Crypto 加密库能够完整的支持 OpenSSL 库,所以会 更加方便点。而且这个库中包含有 RSA 非对称加密算法(M2Crypto.RSA),高级 的加密解密接口(M2Crypto.EVP),还能操作 X.509 证书(M2Crypto.X509)。我们 可以先通过 M2Crypto 库里的模块来生成证书、公钥文件和私钥文件,后面再利 用生成的证书、私钥和公钥来实现加密解密及数字签名认证。(This experiment is based on a widely tested public encryption library to implement digital signature services. Here is the choice The M2Crypto encryption library is implemented, and the M2Crypto encryption library can fully support the OpenSSL library, so it will It's more convenient. And this library contains a RSA asymmetric encryption algorithm (M2Crypto.RSA), high level The encryption and decryption interface (M2Crypto.EVP) can also operate the X.509 Certificate (M2Crypto.X509). We A certificate, a public key file, and a private key file can be generated by the modules of the M2Crypto repository first, and the later will be beneficial. The encrypted decryption and digital signature authentication are realized with the generated certificate, private key and public key.)

文件列表:

证书加密解密
证书加密解密\1.pdf, 765805, 2017-12-19
证书加密解密\python2.py, 6494, 2017-06-06
证书加密解密\sign-cret.cer, 1350, 2017-06-07
证书加密解密\sign-private.pem, 1704, 2017-06-07
证书加密解密\sign-public.pem, 451, 2017-06-07

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • 学生成绩核算系统的设计与实现(25) 要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 (2)三个成绩对总评成绩的百...
    学生成绩核算系统的设计与实现(25) 要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 (2)三个成绩对总评成绩的百分比被定义为常数,各占总成绩的30 、30 和40 。 (3)计算每位学生的总评成绩。 (4)计算该班级本课程的总平均成绩。 (5)计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优,89-80为良,79-70为中,69-60为及格,60分以下为不及格。 (6)按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop
    2022-03-15 21:39:52下载
    积分:1
  • mppt-wind_asser
    说明:  simulation of generator speed with mppt control
    2019-05-10 21:08:24下载
    积分:1
  • CNN
    说明:  测试可运行的卷积神经网络matlab实现(CNN code for running)
    2021-04-15 09:43:37下载
    积分:1
  • 整流电路
    说明:  12脉波,6脉波,以及PWM整流的simulink仿真模型(Simulink simulation model of 12 pulse, 6 pulse and PWM rectifier)
    2020-06-18 13:41:00下载
    积分:1
  • Java手机射击游戏
    Java手机射击游戏,很小的J2me游戏源码,以前运行在诺基亚手机上,现在研究一下,对学习Android游戏有帮助。
    2022-03-20 16:14:22下载
    积分:1
  • 软件设计文档国家标准
    软件设计文档国家标准 -National standards for software design documents
    2022-07-24 00:55:05下载
    积分:1
  • 3
    一款基于jQuery+CSS3+HTML5实现的折叠卡片式下拉菜单特效代码,有一种3D立体效果的下拉菜单代码。(A jQuery+CSS3+HTML5 based folding card drop-down menu special effect code, has a 3D stereoscopic effect of the drop-down menu code.)
    2018-07-27 12:33:46下载
    积分:1
  • FDTD_Shengzijingti
    详细介绍了声子晶体的带隙计算和传输特性,包含声子晶体的计算源程序。内有文件注释。(Details of the phononic crystal band gap calculation and transmission characteristics, including the calculation of phononic crystal source. There are paper notes.)
    2008-03-26 15:33:50下载
    积分:1
  • jibuqiUI
    说明:  A simple pedometer UI project source code, only UI part, there is an orange circular progress bar, can display the scale and steps, change the number of steps can change the numerical ratio at the same time.
    2019-04-25 20:42:24下载
    积分:1
  • 01
    討論了2×2 MIMO信道 使用 ML detection(ML detection for 2 *2 MIMO channel is discussed.)
    2020-06-23 21:20:01下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载