登录
首页 » Fortran » VUMT-Tsai-Wu

VUMT-Tsai-Wu

于 2020-05-19 发布
0 196
下载积分: 1 下载次数: 4

代码说明:

说明:  复合材料VUMAT层压板三维分析,失效准则为蔡-吴失效(Three dimensional analysis of composite laminates using VUMATwith Tsai-Wu failure criterion)

文件列表:

VUMT-Tsai-Wu.for, 4380 , 2020-05-18

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • yf
    低周反复荷载下两跨三层钢筋混凝土框架 滞回模拟(Hysteretic simulation of two-span and three-storey reinforced concrete frame under low cyclic repeated loading)
    2019-04-04 11:09:48下载
    积分:1
  • Introducing Python
    说明:  This book will introduce you to the Python programming language.
    2020-06-19 22:35:07下载
    积分:1
  • FPGA的特点及应用 jiaoshu fpgade yongtu
    FPGA的特点及应用 jiaoshu fpgade yongtu-wu
    2022-03-19 10:36:12下载
    积分:1
  • 使用VC++平台开发的扫雷游戏,基本功能和windows自带的差不多
    使用VC++平台开发的扫雷游戏,基本功能和windows自带的差不多-Use VC++ Platform development of mine-clearing game, the basic functions and windows built-in almost
    2022-03-04 05:38:25下载
    积分:1
  • 距离波门拖引实例
    利用matlab编程,得到雷达距离波门拖引的程序,同时仿真的结果也在上面。(The program of radar range gate drag is obtained by MATLAB programming, and the result of simulation is also above.)
    2018-06-11 16:24:13下载
    积分:1
  • RestoreDB sql server 2012
    说明:  example of restore db sql server
    2019-05-06 23:46:50下载
    积分:1
  • AD9643_EVALCZ_04302014_0528pm
    说明:  adc code for lvds connection
    2019-05-30 15:54:15下载
    积分:1
  • 安富莱_STM32-V4开发板_μCOS-III教程(V0.1a)
    目前关于ucosIII教程比较少,此教程比较详细的列出了UCOS开发过程,开发手册必备,(At present, there are relatively few ucosIII tutorials. This tutorial gives a detailed list of the UCOS development process.)
    2018-05-08 16:46:52下载
    积分:1
  • mmWave_Channel_Model-master
    说明:  毫米波MIMO信道,各种场景下的毫米波MIMO信道(Millimeter wave MIMO channel)
    2020-11-03 14:51:23下载
    积分:1
  • 算法实现题 最长公共子序列问题 给定两个序列 X = { x1 , x2 , ... , xm } Y = { y1 , y2 , ... , yn...
    算法实现题 最长公共子序列问题 给定两个序列 X = { x1 , x2 , ... , xm } Y = { y1 , y2 , ... , yn } 求X和Y的一个最长公共子序列 举例 X = { a , b , c , b , d , a , b } Y = { b , d , c , a , b , a } 最长公共子序列为 LSC = { b , c , b , a }-Algorithm to achieve the longest common sub-title sequence of the problem given two sequences X = (x1, x2, ..., xm) Y = (y1, y2, ..., yn) for X and Y, a maximum common substructure sequence, for example X = (a, b, c, b, d, a, b) Y = (b, d, c, a, b, a) the longest common sub-sequence for LSC = (b, c, b, a )
    2022-03-02 12:22:07下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载