KIM模型

π／4DQPSK抗噪声性能仿真与分析,基于扩频和CDMA系统(π/4DQPSK anti-noise performance simulation and analysis, based on spread spectrum and CDMA systems)

应用于图像处理非常好的维纳滤波！！！，内有注释，简单易懂(applied to image processing very good Wiener filter! ! ! , The Notes are simple to understand!)

基于matlab编写，能够批量读入文件夹内的图像，进行边缘检测，并求出图像中圆形边界的最大径(it can get the maxmum diameter of a circle in series image)

RSSI，TOA定位性能对比，比较好的参考文章(RSSI, TOA positioning performance comparison, good reference articles)

基于逆系统法的荷载识别程序，对于模型简单的识别效果较好(Based on the method of inverse system load identification procedures for the simple model, good recognition effect)

2fsk信号的MATLAB调制，已运行过，正确(2fsk MATLAB signal modulation, has been run over, the correct)

利用cordic实现开方和atan运算的matlab源码。 本人原创，标准cordic算法。(calculate aquare root and atan by cordic. Matlab m language.)

正交频分复用其主要思想是：将信道分成若干正交子信道，将高速数据信号转换成并行的低速子数据流，调制到在每个子信道上进行传输。正交信号可以通过在接收端采用相关技术来分开，这样可以减少子信道之间的相互干扰 ICI 。(Orthogonal Frequency Division Multiplexing)

this code is for matlab antenna and EM modeling

前一段时间我有睡眠问题。我曾经躺在床上，盯着天花板，几个小时。后来有一天，我的外婆建议我试着数羊后，我已经上床睡觉。与往常一样，当我的奶奶暗示的东西，我决定尝试一下。唯一的问题是，有没有羊的时候，我就去睡觉各地进行计数。 创意，因为我，这是不会阻止我。我坐下来写，使得字符，其中＃代表羊的网格，而计算机程序。草（或任何你喜欢的，只是没有羊）。为了使计算更有趣，我也决定要数绵羊，而不是单一的成群的牛羊。两只羊在同一个群，如果他们都有一个共同的一面（上，下，左或右）。另外，如果羊A是在同一羊群如羊B和羊B处于同一羊群如羊℃，然后羊A和C是在同一个群。 现在，我已经有了一个新的问题。虽然这些计数羊居然帮我睡着了，我觉得这是非常无聊的。为了解决这个问题，我决定我需要做的计数为我另一台计算机上的程序。然后，我就可以只启动这两个程序之前，我去睡觉，我会睡个好觉，直到没有任何干扰的早晨。我需要你给我写的这个程序。(A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I d gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed. Creative as I am, that wasn t going to stop me. I sat down and wrote a computer program that made a grid of characters, where# represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock. Now, I ve got a new problem. Though counting these sheep actually helps me fall asleep, I find)