刹车系统测试

一个简单实用的网络TCP/IP测试程序源代码，不修改 即可完成普通测试，在此基础上修改后，即可得到特定的程序。-a simple and practical network TCP/IP testing program"s source code can be completed without amending the general test, on the basis of this revision, can be a particular procedure.

说明：  一个使用NI-pIX6002的labview数据采集程序，可以储存、发送数据，显示波形，(A LabVIEW data acquisition program that uses NI-pIX6002 to store, send and display the waveform.)

说明：  本VI示范了如何通过LabVIEW自身的强大编程能力，开发一套通用的多通道数据采集监测数据库系统。VI包括了主显示界面、用户权限管理、数据采集、超限报警、配置、实时曲线、历史曲线、日志记录、等数据库管理功能。(This VI demonstrates how to develop a common multi-channel data acquisition monitoring database system with LabVIEW's powerful programming capabilities. VI includes the main display interface, user rights management, data collection, overrun alarm, configuration, real-time curve, history curve, log records, and other database management functions.)

1．在内存中开辟一个虚拟磁盘空间作为文件存储器，在其上实现一个简单的单用户文件系统。在退出这个简单的文件系统时，应将该虚拟文件系统保存到磁盘上，以便下次可以再将它恢复到内存的虚拟磁盘空间中。 2．文件存储空间的分配可采用显式链接分配或其他的办法。 3．空闲空间的管理可选择位示图或其他的办法。如果采用位示图来管理文件存储空间，并采用显示链接分配方式，那么可以将位示图合并到FAT表中。 4．文件目录结构采用多级目录结构。为了简单起见，可以不使用索引结点，其中的每个目录项应包含文件名、物理地址、长度等.(1.making a virtual diskete memory as file storyge,in this district it can implement a simple single user file system .when quit this simple file system ,it shoud save the virtual file system to diskete,then it can be resumed to virtual diskete district in the memory.3.we can choose location hint map to manage the idle space or orther means.if we choose locationhint map to manage file saving space,and adopt show linking distribution mode,we can combine location hint map into FAT table.4.file directory confiuration adopts multilevel directory confiuration.to simplify,it doesn t use index dot,evrery term shoud include file name,physical dress and lenght.)

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多线程服务器源代码，基于winsock2编写-server_mutilthread.cpp，base on winsock2

QOS流量控制，利用QOS编程，简单易懂，是个很好的源程序。-QOS flow control, use of QOS programming, easy to understand, are a good source.

blind source separation

采用VC++编程，实现局域网内部的聊天小程序。-Used VC++ Programming, internal LAN chat applet.

利用动态规划法，求出字符串A变为字符串B的最小操作数。（每次只能操作一个字符）(Find the minimum operand that turns string A into string B)