结构动力学

机器视觉理论PPT,入门者可看下，主要介绍一些机器视觉入门内容(Machine vision theory PPT, beginners can look, introduces some of the machine vision getting started)

说明：  最好用的源码 DLL:=TDXDLL1(1,H,L,5); HIB:=TDXDLL1(2,DLL,H,L); LOB:=TDXDLL1(3,DLL,H,L); SIG:=TDXDLL1(4,DLL,H,L); BSP:=TDXDLL1(5,DLL,H,L); SLP:=TDXDLL1(8,DLL,H,L); IF(HIB,HIB,DRAWNULL), COLORYELLOW; IF(LOB,LOB,DRAWNULL), COLORYELLOW; STICKLINE(SIG,LOB,HIB,0,0), COLORYELLOW; DRAWLINE(DLL=-1,L,DLL=+1,H,0), COLORYELLOW; DRAWLINE(DLL=+1,H,DLL=-1,L,0), COLORYELLOW; DRAWNUMBER(DLL=+1,H,SLP), COLORYELLOW, DRAWABOVE; DRAWNUMBER(DLL=-1,L,SLP), COLORYELLOW; BUY(BSP=3,LOW); SELL(BSP=12,HIGH); BUYSHORT(BSP=2,LOW); SELLSHORT(BSP=13,HIGH);(cmake --build . --config Debug)

Beckhoff官方CoE样例，功能框架已实现PDO，SDO(Beckhoff official CoE sample)

说明：  SLIC算法是simple linear iterative cluster的简称，该算法用来生成超像素（superpixel） 算法步骤： 已知一副图像大小M*N,可以从RGB空间转换为LAB空间，LAB颜色空间表现的颜色更全面 假如预定义参数K，K为预生成的超像素数量，即预计将M*N大小的图像(像素数目即为M*N)分隔为K个超像素块，每个超像素块范围大小包含[（M*N）/K]个像素 假设每个超像素区域长和宽都均匀分布的话，那么每个超像素块的长和宽均可定义为S，S=sqrt(M*N/K) 遍历操作，将每个像素块的中心点的坐标(x,y)及其lab的值保存起来，加入到事先定义好的集合中(Algorithmic steps: Given the size of an image M*N, it can be converted from RGB space to LAB space, and the color space of LAB is more comprehensive. If the predefined parameter K, K is the number of pre-generated super-pixels, i.e., the image of M*N size (the number of pixels is M*N) is expected to be divided into K super-pixel blocks, each of which contains [(M*N)/K] pixels. Assuming that the length and width of each super-pixel region are evenly distributed, the length and width of each super-pixel block can be defined as S, S = sqrt (M*N/K). The traversal operation saves the coordinates (x, y) and lab values of the central points of each pixel block and adds them to a pre-defined set.)

C++ INPUT_OUTPUT using iostream in console application

vc++的视频，用flash player播放，例如175其中17代表第17章，而5代表第17章的第5个视频(vc++ the video, use flash player to play, for example, 175 of which 17 on behalf of Chapter 17, and 5 on behalf of Chapter 17 of the first five video)

说明：  H5获取定位信息，需要HTTPS支持，有没有更方便点的啊(H5 positioning information, need HTTPS support, have a more convenient point)

编写strcpy函数,虽然简单,但是能检验出点水平的一个练习,在高质量c里有介绍.-Prepared strcpy function, although simple, but it can be tested at a practice level, in the introduction of high-quality c-ri has.

说明：  通过点云三维坐标，构件可用于3D打印的stl文件(Through point cloud three-dimensional coordinates, components can be used for 3D printing STL files)

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