张文军MATLAB仿真

4进制振幅键控的源代码，运行后得到正常结果！(4 binary amplitude shift keying of the source code, running the results are normal!)

说明：  有频带方差和谱熵法。自己实现加窗分帧。里面设计傅里叶变换还有矩阵的运算。(speech endpoint detection. frequence_diff and pushang.)

这本关于元胞自动机的教材结合了matlab例程，讲解生动，读者朋友可以自己尝试建立自己的元胞自动机模型(This textbook on cellular automata combines the MATLAB routine with a vivid explanation that readers can try to build their own cellular automata model.)

说明：  双闭环控制系统的MATLAB仿真及其说明。很不错的模块。(SPEED & POSITION PID MATLAB)

共享热门的一个谱相减程序，比较完整的程序(share of a hot spectral subtraction procedures, the procedures for a more comprehensive)

power_transfo.rar,功率电子领域matlab仿真文件，已经验证过，程序运行正常(power_transfo.rar,Power electronics field matlab simulation file, has already been verified, the normal operating procedures)

本算例用正交多项式，采用最小二乘法拟合散点函数曲线，程序为MATLAB编写！(zuixiao ercheng duoxiangshi)

经典功率谱估计方法——直接法和间接法,以及改进的经典功率谱估计方法-Welch法(Classic power spectral estimation methods- direct and indirect methods, as well as improvements to the classic power-Welch method of spectral estimation method)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

用MATLAB实现的SUSAN算子，用于图像的边缘检测(susan detect edge!)