Ebadi

顺序表插入x值顺序表插入x值顺序表插入x值(Insert x value of the order sequence table table table is inserted into the x value of the order value of x)

ESP8266WiFi杀手固件 包括烧录软件(ESP8266 WiFi Killer Firmware in Chinese incloud IDE)

深度图片采集, 用于3D结构光的测试．人脸识别，活体检测(depth images, for face detector and alive test)

计算机专业算法学习的实习练习 希望对大家有所帮助(Computer algorithm to study the practice of professional practice for all of us want to be helpful)

房子揭计算器项目文件，可以以等额或等本方式进行计算出每笔的本金和利息。(House mortgage calculator project file can be equal or equivalent calculated in this way each of the principal and interest.)

说明：  LCD9431 stm32驱动 并行总线 显示文字和图片(Lcd9431 STM32 drives parallel bus to display text and pictures)

AD环境下常用有源晶振的原理图库和封装库(AD environment commonly used active crystal package library and schematic library)

picc程序，用于湿度传感器sht15系列(picc procedures, for the humidity sensor sht15 series)

VC++枣子穿纽游戏源码，类似扫雷游戏的界面，不过玩法有点不一样，游戏源代码在vc++6下编译通过，你应该通过源代码能看出些玩法来。 　　相关资料：在本游戏中，你将作为一名裁缝，将尽可能多的纽扣穿成一个闭合的路线。游戏初始有 15 个纽扣，随着时间的增加，纽扣数目也增加，当达到70个时游戏即结束。只能在有纽扣的点穿线，且只能在水平方向或竖直方向穿线。线可交叉，但有纽扣的点不能交叉连接。 　　透露点秘诀：要尽可能使连线长且该连线上的纽扣数多。(VC++ source code dates to wear new game, the game interface similar to mine, but a bit different from playing the game in the source code to compile under vc++6 passed through the source code you should be able to see more options. Relevant information: in this game, you will serve as a tailor, will be wearing buttons as much as possible into a closed line. Game initial 15 buttons, an increase over time, increase the number of buttons, when the 70 hours to reach the end of the game that is. Buttons can only point in the threading, and only in the horizontal direction or vertical direction of threading. Lines cross, but the buttons can not be cross-connect point. Point revealed the secret: To the extent possible, so long and the connection to connect on a few more buttons.)

数控恒流源设计完整的实例，具有很好的学习和借鉴的意义。(The numerical control constant current source design complete example, has the very good study and the reference significance.)