GUI04

一个关于matlat基础的ppt,出学者可以看看 一个关于matlat基础的ppt,出学者可以看看(a ppt about the basis of matlab)

spea2多目标进化算法对两个目标的多目标优化问题的测试(spea2 multi-objective evolutionary algorithm on the two goals of testing multi-objective optimization problem)

说明：  统计学的计算的matlab实现，大家可以好好学习学习了(Matlab achieve statistical calculations, we can learn from studying the)

通过对摄像镜头拍摄得到的图片进行失真复原，确定相应摄像头的固定失真系数，从而解决该摄像镜头的失真问题。(Image captured by the imaging lens distortion recovery, to determine the appropriate camera fixed distortion coefficient, so as to solve the problem of the distortion of the imaging lens.)

利用matlab实现图像中字母获数字的识别。(use matlab to recognized the words or figures)

Places information on a communications pipe. When two threads want to pass data back and forth, one creates a piped writer and the other creates a piped reader.

单相全桥逆变器模型，测试OK，直接运行，需要的参考(Single phase full bridge inverter model)

卡尔曼滤波MATLAB代码，卡尔曼作为经典滤波被已广泛用于在线处理数据应用中(MATLAB code Kalman filter, Kalman filter as a classic is already widely used for online data processing application)

1.分别在两个图中画出δ(n)和δ(n-2)，其中-10≤n≤10，画出U（n）其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n)，0≤n≤10和x2(n)=(0.8)n，1≤n≤6。 3.由上一题，计算y(n)=x1(n)+x2(n)，并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)

commonsonic公司的ofdm仿真源码，共享出来给大家学习，共同进步(commonsonic company ofdm simulation source code, for Members to share learning and common progress)